4+71. In Millikan's experiment, a potential difference of 2.0is applied between the two plates, which are 8 mmapart, to balance an oil drop of mass 4.9 × 10-4 kg.Calculate the number of elementary charges on thedrop (g = 10 m/s²). (7.6) m106 mlo enters a0.800 T. (8.2) TI(a) Determine the magnitude of the magnetic 101exerted on the proton.(h) Dorcriho thtolrotho proton as it staysOFF/NO2nd FCAMODESTAT VARALPHASNIDELSET UPRESETarc hypNOT sin1AND cos OR tan XOR DRGXNORdhysinCOSDRGD 10 EAujDEGSTOExpabcD°M'SDATA CD.-xy oyRANDOM re6sx*nPr ox CHEX CBINrju5.2.1.ANS3.DEC

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71. In Millikan's experiment, a potential difference of 20k is applied between the two plates, which are 8 mm apart, to balance an oil drop of mass 4.9 × 10-14 ko Calculate the number of elementary charges on the drop (g = 10 m/s²). (7.6) m %3D , 106 mle enters a

71. In Millikan's experiment, a potential difference of 20k is applied between the two plates, which are 8 mm apart, to balance an oil drop of mass 4.9 × 10-14 ko Calculate the number of elementary charges on the drop (g = 10 m/s²). (7.6) m %3D , 106 mle enters a

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalance of only a few electrons. The strength of the electric field was adjusted so that the electric and gravitational forces on a drop would balance and the drop would be suspended in air. In this way the charge on the drop could be calculated. The charge was always found to be a small multiple of 1.6e-19 C. Find the charge on an oil drop weighing 1.94 10-14 N and suspended in a downward field of magnitude 2.42 104 N/C. find E
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