70 kN 50 kN 50 kN F 6 m A E В D -4 at 4 m = 16 m 10. Member CD is a. 41.67kN (C) b. 100kN (C) c. 113.33kN (T) d. 41.67kN (T) 11. Member CH is a. 41.67kN (C) b. 100kN (C) c. 113.33kN (T) d. 41.67KN (T) 12. Member GH is 41.67KN (C) b. 100kN (C) c. 113.33kN (T) d. 41.67kN (T) а.

Q: 3. Determine the moment at each support of the continuous beam shown. Make at least five…

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Q: 8a kN a kN/m A -4.00- -6.00–

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Q: 13. Find the moment at B. a. -192.5 kN. m. b.-468.75 kN. m C. -600 kN. m d. -234.38 kN. m

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Q: SOLVE FOR SHEAR FO DIAGRAM AND SHEA MOMENT DIAGRAM

A: degree of static indeterminacy, Ds = number of unknown support reactions - number of equilibrium…

Q: 4 kN Draw F.B.D then find reactions at supports A and B take beam AB wieght 20K g Ax B Rgsin30 30°…

A: Given that: FBD of a beam as shown:

Q: Shear/Moment Diagram

A:

Q: Solve for Shear the and moment diagram 9.35 KN /m reactions and draw the श्र 1 2m 5m 116 KN 5m 9.35…

A: As multiple questions are asked and as per the guidelines only very first question will be…

Q: P=10 KN 3.75m 1.25 m 5m 71. Find the deflection under point of application of concentrated load P.…

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Q: Determine the shear (in kN) In member AB using Portal Method. Input the magnitude only. P=50KN B C…

A: Given data in question  Span member length  Point load Portal method To find out  Shear force in…

Q: 20 kN A 30 kN/m F B 16 kN =10 C 2m 4m 4m 3m Which of the following most nearly gives the maximum…

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Q: 18.2 kN/m 36.4kN/m

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Q: 15kN 12kN 10KN 40KN/m 30KN/m 20KN/m OB C 1.50m 2.50m 2.50m 2.50m 3.00m 1.00m 4.00m 5.00m 4.00m

A:

Q: Using MDM, what is the reaction at support D? 4 kN 20 kN 18 kN 4 kN/m A B C. D 2m 6m 2m 2m 4m Select…

A: Finding out reaction at support D.

Q: 15 kN/m D E 6 m 9 m 12 kN/m A 10 m 5 m

A: To draw SFD and BMD

Q: A. -120 kN-m B. -130 kN-m C. -135 kN-m D. none of the above   What is the maximum moment? A. 122…

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Q: Which section below has the larger negative moment capacity?

A: The negative moment capacity for sections A and B:Section A details:b = 200 mmd = 600 mm4 -25 mm…

Q: reaction value and direction of the hinge support 3m 3m 4m 50 kN 50 KN up 116.66 KN down 116.66 KN…

A:

Q: A Beam AB is supported by a pin at A and cable BC at B. The force developed in cable BC is. 250 N…

A: Step 1

Q: DET FRMINE THE SLOPE KTA AND DEFLECTION AT C OF THE OVER HAWC BEAM I= 45.5 (104) ma? E= 200 GPa 30…

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Q: 20. What would be reaction at A. b. 390 kN d. 300 kN a. 487.5 kN c. 187.5 kN 21. What would be…

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Q: 9.35 KN /m 2m SOLVE FOR SHEAR FORCE DIAGRAM AND SHEAR MOMENT DIAGRAM 116 KN CS Scanned with…

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Q: Three force P3D36, F=54, and Q=72 KN, C D 4 m E 3m 3 m 3 m 3m A H G F D. force in member EF force in…

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Q: weight 3718 N is supported by three links as shown.  1-  The magnitude of internal force in AB is:(…

A: Using vector analysis, express each bar force as a Cartesian vector.Then using equilibrium equations…

Q: 4) Determine the absolute maximum moment in the beam due to the loading shown.

A: To determine:The absolute maximum moment in the beam due to the loading shown.

Q: Design the torsional and shear reinforcement for the beam as shown in the figure. The resulting L…

A: Given data- Span L = 14 m Z = 2.4 m h = 800 mm Width b = 400 mm Thickness t = 150 mm d = 735 mm fc =…

Q: 15kN 12kN 10KN 40KN/m 30KN/m 20kN/m A OB C_O 1.50m 2.50m 2.50m 2.50m 3.00m 4.00m 4.00m 5.00m 4.00m

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Q: Axis of rotoinversion indicates إختر أحد الخيارات: translation + inversion .a O penetration +…

A: Brief concept introduction- Axis of rotoinversion- Rotation around a rotation axis is combined with…

Q: SET 5: 100 kN w = 40kN/m С 5m Зт р A 8m OB 10т THREE MOMENT EQUATION METHOD 14) What is the maximum…

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Q: 50 k 2 k/ft 10 ft 3 k/ft 24 ft 12 ft -12 ft- 8. The vertical support reaction at hinge is b. 61.28k…

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Q: The beam in the figure below is fabricated by attaching a C180x14.6 channel to a W250x17.9 shape…

A: Given, Maximum Shear force =Vmax=65 KN C180X14.6 A1=1850 mm2d=178 mmxcg=13.8 mmIY=I1=0.405×106…

Q: 50 k 2 k/ft 10 ft 3 k/ft 24 ft 12 ft -12 ft- 8. The vertical support reaction at hinge is b. 61.28k…

A:

Q: Calculate the value of the bending moment generated at suppOrt A of the given structure? 120 kN 40m…

A: Finding out moment at A.

Q: 1. Б 2т 3rd day 8 kr/m , кури эт mil

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Q: solve the indeterminate structure using moment distribution method

A:

Q: Draw the freebody diagram

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Q: 30 41 Determine the 5m 3. Resultant of the following forces and moment a bout 3m 120 KN.m lo kN 2 m

A: Solution Given Diagram

Q: 8- Detennine the bending moment at point D the structure shown. (C,-437.5 kN) 25 kN/m 13 Hinge Hinge…

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Q: ID 15k00/m 2h Support Reachs

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Q: Calculate the a.) Double deflection Integration b.) Area- Moment at point E Method Method c.)…

A: NOTE : Since you have asked multiple methods we will solve the first method for you. If you want any…

Q: Construct the load, shear, and moment diagrams for the fol-

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Q: Determine the moment at point B for the beam shown. 100 kN - m 150 kN 25 kN/m B - 4 m- 2m 2 m O a.…

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Q: am is having a fixed support in one end, and 2 roller support 3m a from the fixed support,…

A: The structure is statically indeterminate. Using moment distribution method the end moments can be…

Q: 50 kN 40 kN/m 10 kN/m B.) OB 20kN-m 1m 1m 2 m- 2 m+ 4 m

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.