Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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### Thermodynamics of Aluminum Oxide Decomposition

**Reaction Equation:**
\[ \text{Al}_2\text{O}_3 (s) \rightarrow 2 \text{Al} (s) + \frac{3}{2} \text{O}_2 (g) \]
\[ \Delta H_{\text{rxn}} = 1676 \text{ kJ} \]

#### Question 1:
**Is this reaction endothermic or exothermic?**
- [Choose]  
- 1676 kJ  
- 440 kJ  
- endothermic  
- 1760 kJ  
- 879 kJ  
- exothermic  

#### Question 2:
**If 1.049 moles of aluminum were formed by the reaction, how much heat (kJ) would be involved?**

---

**Explanation:**

The provided image contains a chemical reaction where aluminum oxide (\(\text{Al}_2\text{O}_3\)) decomposes into aluminum (\(\text{Al}\)) and oxygen gas (\(\(\text{O}_2)\)). The reaction has an enthalpy change \(\(\Delta H_{\text{rxn}}\)) of 1676 kJ. The nature of the reaction, whether it is endothermic or exothermic, needs to be determined by identifying whether heat is absorbed or released. Additionally, if a specific amount of aluminum is formed, the heat involved in the reaction can be calculated.

- **Endothermic Reaction:** Absorbs heat from the surroundings (\(\Delta H > 0\)).
- **Exothermic Reaction:** Releases heat to the surroundings (\(\Delta H < 0\)).

Given that \(\(\Delta H_{\text{rxn}}\)) is a positive value (1676 kJ), this reaction is endothermic, meaning it absorbs heat.

For calculating the heat involved when 1.049 moles of aluminum are formed:
- According to the stoichiometric equation, 2 moles of aluminum require 1676 kJ of heat.
- For 1.049 moles of aluminum:
\[ \text{Heat involved} = \frac{1676 \text{ kJ} }{2} \times 1.049 = 440 \text{ kJ} \]

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Transcribed Image Text:### Thermodynamics of Aluminum Oxide Decomposition **Reaction Equation:** \[ \text{Al}_2\text{O}_3 (s) \rightarrow 2 \text{Al} (s) + \frac{3}{2} \text{O}_2 (g) \] \[ \Delta H_{\text{rxn}} = 1676 \text{ kJ} \] #### Question 1: **Is this reaction endothermic or exothermic?** - [Choose] - 1676 kJ - 440 kJ - endothermic - 1760 kJ - 879 kJ - exothermic #### Question 2: **If 1.049 moles of aluminum were formed by the reaction, how much heat (kJ) would be involved?** --- **Explanation:** The provided image contains a chemical reaction where aluminum oxide (\(\text{Al}_2\text{O}_3\)) decomposes into aluminum (\(\text{Al}\)) and oxygen gas (\(\(\text{O}_2)\)). The reaction has an enthalpy change \(\(\Delta H_{\text{rxn}}\)) of 1676 kJ. The nature of the reaction, whether it is endothermic or exothermic, needs to be determined by identifying whether heat is absorbed or released. Additionally, if a specific amount of aluminum is formed, the heat involved in the reaction can be calculated. - **Endothermic Reaction:** Absorbs heat from the surroundings (\(\Delta H > 0\)). - **Exothermic Reaction:** Releases heat to the surroundings (\(\Delta H < 0\)). Given that \(\(\Delta H_{\text{rxn}}\)) is a positive value (1676 kJ), this reaction is endothermic, meaning it absorbs heat. For calculating the heat involved when 1.049 moles of aluminum are formed: - According to the stoichiometric equation, 2 moles of aluminum require 1676 kJ of heat. - For 1.049 moles of aluminum: \[ \text{Heat involved} = \frac{1676 \text{ kJ} }{2} \times 1.049 = 440 \text{ kJ} \] The dropdown menus below each question facilitate user interaction to select the correct answer based on their understanding of
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