7. The tetraethyl lead, Pb(C2H5)4 in a 25.00 mL sample of gasoline was shaken with 15.00 mL of 0.02095 M I2. The reaction is Pb(C2H5)4 + I2 → Pb(C2H5)3I + C2H$I After the reaction was complete, the unused I2 was titrated with 6.09 mL of 0.03465 M NazS2O3. I2 + 2NA2S2O3 2Nal + NazS4Os Calculate the weight in milligrams of Pb(C2HS)4 (323.4 g/mol) in each milliliter of the gasoline. [ 8.100 5.400 2.700 10.80 ] mg/mL

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7. The tetraethyl lead, Pb(C2H5)4 in a 25.00 mL sample of gasoline was shaken with 15.00 mL of 0.02095 M I2. The
reaction is Pb(C2H5)4 + I2 → Pb(C2H5)3I + C2H$I
After the reaction was complete, the unused I2 was titrated with 6.09 mL of 0.03465 M NazS2O3.
I2 + 2NA2S2O3 2Nal + NazS4Os
Calculate the weight in milligrams of Pb(C2HS)4 (323.4 g/mol) in each milliliter of the gasoline.
[ 8.100
5.400
2.700
10.80 ] mg/mL
Transcribed Image Text:7. The tetraethyl lead, Pb(C2H5)4 in a 25.00 mL sample of gasoline was shaken with 15.00 mL of 0.02095 M I2. The reaction is Pb(C2H5)4 + I2 → Pb(C2H5)3I + C2H$I After the reaction was complete, the unused I2 was titrated with 6.09 mL of 0.03465 M NazS2O3. I2 + 2NA2S2O3 2Nal + NazS4Os Calculate the weight in milligrams of Pb(C2HS)4 (323.4 g/mol) in each milliliter of the gasoline. [ 8.100 5.400 2.700 10.80 ] mg/mL
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