7. Refer to the circuit below. a. Find the Norton equivalent circuit external to RL. b. Use the equivalen circuit to determine IL when RL = 20 Q and when RL = 50 Q. R1 16 0 IL R2 24 N 0.2 A RL ( 20 N→50 N 2.4 V

Tutorial exercise Jimmy the Circuit Builder is at it again and this time he is using AC. He has all of the linear components in pairs: two AC voltage sources, two AC current sources, two resistors, two capacitors and two inductors. He is trying to build circuits to create certain voltages and currents. All of the sources operate at w=500 rad/s. 940° V 2 <90° A - 12<60° V 1-30° A (c) V=6490° V (d) I=64150° A (e) I = 0.6 +j1.04 (f) V=18.25434.7° V + (a) Draw the circuit. (b) Calculate the voltage across each component. 100μF TE 1mF 46 392 -M 1mH hint: try combining the two sources 10mH Jimmy first builds one circuit to check his understanding of AC voltage, current and power. The circuit is a series connection of the 12 <60° V voltage source, the 3 resistor, the 10 mH inductor, and the 1mF capacitor. 1092 M Using only two elements, connect the pair of elements to create the following AC voltage and currents: Using exactly three elements, draw circuits to create the following AC voltage…

Use source transformation to find the output current loin the circuit given below, where V₁ = 40 30° V, XL = 50 2₂ Xc= 2002, R₁ = R₂ = 80 02, and V2 = 100 V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. jXL V₁ R₁ www R₂ www -jXc The output current in the given circuit is V₂ °A.

Homework problem issue...Can I get a step by step please? TIA