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7. Poisson: accidents. An average of A 3 accidents per year occurs along the I-95 stretch of highway between Michigan City, Indiana, and St. Joseph, Michigan. (a) Expectation. The expected number of accidents is µ = E(X) = \ = (i) 1 (ii) 2 (iii 3 (iv) 4. (b) Expected cost. If it costs $500,000 per accident, the expected yearly cost is E(C) = E(500000X) = 500000E(X) = 500000(3) = (i) $500, 000 (ii) $1,000, 000 (iii) $1,500, 000 (iv) $2,000,000. %3D %3D ction 6. Functions of a Random Variable (LECTURE NOTES 4) 63 (c) Variance., The variance in the number of accidents per year is o² = Var(X) = d = (i) 1 (ii) 2 %3D %3D (iii) 3 (iv) 4. (d) Standard deviation. Standard deviation in number of accidents per year o = VA= V3= (i) 1.01 (ii) 1.34 (iii) 1.73 (iv) 1.96. %3D

7. Poisson: accidents. An average of A 3 accidents per year occurs along the I-95 stretch of highway between Michigan City, Indiana, and St. Joseph, Michigan. (a) Expectation. The expected number of accidents is µ = E(X) = \ = (i) 1 (ii) 2 (iii 3 (iv) 4. (b) Expected cost. If it costs $500,000 per accident, the expected yearly cost is E(C) = E(500000X) = 500000E(X) = 500000(3) = (i) $500, 000 (ii) $1,000, 000 (iii) $1,500, 000 (iv) $2,000,000. %3D %3D ction 6. Functions of a Random Variable (LECTURE NOTES 4) 63 (c) Variance., The variance in the number of accidents per year is o² = Var(X) = d = (i) 1 (ii) 2 %3D %3D (iii) 3 (iv) 4. (d) Standard deviation. Standard deviation in number of accidents per year o = VA= V3= (i) 1.01 (ii) 1.34 (iii) 1.73 (iv) 1.96. %3D

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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7. Poisson: accidents. An average of X 3 accidents per year occurs along the I-95 stretch of highway between Michigan City, Indiana, and St. Joseph, Michigan, (a) Expectation. The expected number of accidents is µ = E(X) = 1 = (i) 1 (ii) 2 (iii 3 (iv) 4. (b) Expected cost. If it costs $500,000 per accident, the expected yearly cost is E(C) = E(500000X)= 500000E(X) = 500000(3) (i) $500, 000 (ii) $1,000, 000 (iii) $1,500, 000 (iv) $2, 000, 000. %3D %3D Section 6. Functions of a Random Variable (LECTURE NOTES 4) 63 (c) Variance. The variance in the number of accidents per year is o² = Var(X) =1 = (i) 1 (ii) 2 (iii 3 (iv) 4. %3D (d) Standard deviation. Standard deviation in number of accidents per year = VX = V3~ (i) 1.01 (ii) 1.34 (iii) 1.73 (iv) 1.96.
Transcribed Image Text:7. Poisson: accidents. An average of X 3 accidents per year occurs along the I-95 stretch of highway between Michigan City, Indiana, and St. Joseph, Michigan, (a) Expectation. The expected number of accidents is µ = E(X) = 1 = (i) 1 (ii) 2 (iii 3 (iv) 4. (b) Expected cost. If it costs $500,000 per accident, the expected yearly cost is E(C) = E(500000X)= 500000E(X) = 500000(3) (i) $500, 000 (ii) $1,000, 000 (iii) $1,500, 000 (iv) $2, 000, 000. %3D %3D Section 6. Functions of a Random Variable (LECTURE NOTES 4) 63 (c) Variance. The variance in the number of accidents per year is o² = Var(X) =1 = (i) 1 (ii) 2 (iii 3 (iv) 4. %3D (d) Standard deviation. Standard deviation in number of accidents per year = VX = V3~ (i) 1.01 (ii) 1.34 (iii) 1.73 (iv) 1.96.
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