Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Please solve questions 7,8 and 9.

A lower bound for II(N). In this question we will prove that there are infinitely many primes by examining the prime counting function II(N), where II(N) = The number of primes between 2 and N We say that a natural number n 2 2 is square-free if it is not divisible by a square. For example, 6 is square-free, but 8 is not, since it is divisible by 4 = 22. 1. Use the fundamental theorem of arithmetic to show that every integer n > 2 can be written as a product n = 8•r2, where s, r > 1 are integers and s is square-free. We call this the square-free factorization. 2. For example, the square-free factorization of 8 = 2· (2)2 (s = 2, r = 2) and of 600 = 6 · 102 (s = 6, r = 10.) Find the square-free factorization of 72 and 2366. 3. Define S(N) = The number of squares between 1 and N F(N)= = The number of square-free numbers between 1 and N What is S(4), S(25) and S(49)? F(6) and F(50)? 4. In part 1, we showed that every positive integer factors uniquely as a product of a square and square-free number. Use this to conclude that N < S(N) · F(N). In the next parts we'll overestimate both S(N) and F(N). 5. Show that S(N)< N for every N 1. 6. Show that F(N) < 2(N). (Hint: every square free-number smaller than N of the form q1 · q2 · .. · qk where the q; are distinct primes smaller than N.) 7. Now using 4, 5, and 6, we have N < VN - 2(N). Get II(N) by itself on the right-hand side of this inequality. 8. Take the limit from the solved inequality in 6 to conclude that limN II(N) and hence that there are infinitely many primes. = 0 9. Using part 6, what's the smallest N guaranteed to have 500 primes smaller than it?
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Transcribed Image Text:A lower bound for II(N). In this question we will prove that there are infinitely many primes by examining the prime counting function II(N), where II(N) = The number of primes between 2 and N We say that a natural number n 2 2 is square-free if it is not divisible by a square. For example, 6 is square-free, but 8 is not, since it is divisible by 4 = 22. 1. Use the fundamental theorem of arithmetic to show that every integer n > 2 can be written as a product n = 8•r2, where s, r > 1 are integers and s is square-free. We call this the square-free factorization. 2. For example, the square-free factorization of 8 = 2· (2)2 (s = 2, r = 2) and of 600 = 6 · 102 (s = 6, r = 10.) Find the square-free factorization of 72 and 2366. 3. Define S(N) = The number of squares between 1 and N F(N)= = The number of square-free numbers between 1 and N What is S(4), S(25) and S(49)? F(6) and F(50)? 4. In part 1, we showed that every positive integer factors uniquely as a product of a square and square-free number. Use this to conclude that N < S(N) · F(N). In the next parts we'll overestimate both S(N) and F(N). 5. Show that S(N)< N for every N 1. 6. Show that F(N) < 2(N). (Hint: every square free-number smaller than N of the form q1 · q2 · .. · qk where the q; are distinct primes smaller than N.) 7. Now using 4, 5, and 6, we have N < VN - 2(N). Get II(N) by itself on the right-hand side of this inequality. 8. Take the limit from the solved inequality in 6 to conclude that limN II(N) and hence that there are infinitely many primes. = 0 9. Using part 6, what's the smallest N guaranteed to have 500 primes smaller than it?
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