7. Fill in the blank cells based on the information provided. Network Class *CIDR Subnet Mask Address 128.123.0.0 135.45.0.0 193.10.10.0 211.123.83.0 10.0.0.0 32.0.0.0 204.204.5.0 156.35.0.0 116.0.0.0 145.23.0.0 199.12.1.0 15.0.0.0 B /30 /25 /28 /26 /13 /20 /28 /27 /21 /14 /29 /30 /29 255.255.255.252 #Subnets #Hosts/ Subnet 16384 2

7. Fill in the blank cells based on the information provided. Network Class *CIDR Subnet Mask Address 128.123.0.0 135.45.0.0 193.10.10.0 211.123.83.0 10.0.0.0 32.0.0.0 204.204.5.0 156.35.0.0 116.0.0.0 145.23.0.0 199.12.1.0 15.0.0.0 B /30 /25 /28 /26 /13 /20 /28 /27 /21 /14 /29 /30 /29 255.255.255.252 #Subnets #Hosts/ Subnet 16384 2

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Q1/ Implement a network consists of two different networks one of them is of 3 PCs the second is of 2 PCs. The net ID of Network-1 is: 172.16.10.0/16 The net ID of Network-2 is: 172.16.20.0/16
Required Task: Implement a chat system that consists of two processes (Pland P3). The two processes communicate with each other via shared memory. This system works as follows: ✓ P1 takes a string as a command line argument and writs it to the shared memory. ✓P3 reads the shared memory contents, converts it to upper case, and writes it to the terminal.
Scenario: IPv4 addresses (used to communicate on a network) have 4 numbers with 3 decimal points between them with each number being called an octet. For example, 1.2.3.4. 1 is an octet, 2 is an octet, and so on. The first octet has to have values between 1-255 while the 2nd-4th octets can have values between 0-255. The IP addresses are divided into classes A, B, C, D and E based upon the value of the first octet. See the table below. Students preparing for the CompTIA A+ certification (those taking CTS1131 Computer Home/Small Office Essentials and CTS1132 PC Technician who are majoring in CIT, Networking or IT Security) will have the following options to choose from in preparing to study these concepts and need to focus on class A, B and C: 1. Identify the class: Given an IP address, the user answers with an "A", "B" or "C". 2. Provide the default subnet mask: Given an IP address, the user answers with the appropriate default subnet mask. 3. Exit: The program ends. Once the user…
import org.firmata4j.IODevice;import org.firmata4j.Pin;import org.firmata4j.firmata.FirmataDevice;import org.firmata4j.ssd1306.SSD1306;import java.io.IOException;import java.util.HashMap;import java.util.TimerTask;public class minorproj extends TimerTask {static String recLog = "\"/dev/cu.usbserial-0001\"";static IODevice myGroveBoard;private final SSD1306 theOledObject;private Pin MoistureSensor;private Pin WaterPump;private Pin Button;private int sampleCount;public minorproj(SSD1306 theOledObject, Pin Button, Pin MoistureSensor, Pin WaterPump) {this.theOledObject = theOledObject;this.Button = Button;this.MoistureSensor = MoistureSensor;this.WaterPump = WaterPump;this.sampleCount = 0;}double startTime = System.currentTimeMillis();@Overridepublic void run() {while (true) {{// check if button is pressedif (this.Button.getValue() == 1) {break; // exit loop and stop program}String VolValue = String.valueOf(MoistureSensor.getValue());System.out.println("Moisture Sensor Value:" +…
import org.firmata4j.IODevice;import org.firmata4j.Pin;import org.firmata4j.firmata.FirmataDevice;import org.firmata4j.ssd1306.SSD1306;import java.io.IOException;import java.util.HashMap;import java.util.TimerTask;public class minorproj extends TimerTask {static String recLog = "\"/dev/cu.usbserial-0001\"";static IODevice myGroveBoard;private final SSD1306 theOledObject;private Pin MoistureSensor;private Pin WaterPump;private Pin Button;private int sampleCount;public minorproj(SSD1306 theOledObject, Pin Button, Pin MoistureSensor, Pin WaterPump) {this.theOledObject = theOledObject;this.Button = Button;this.MoistureSensor = MoistureSensor;this.WaterPump = WaterPump;this.sampleCount = 0;}double startTime = System.currentTimeMillis();@Overridepublic void run() {while (true) {{// check if button is pressedif (this.Button.getValue() == 1) {break; // exit loop and stop program}String VolValue = String.valueOf(MoistureSensor.getValue());System.out.println("Moisture Sensor Value:" +…
Write code for the InternetThing class to complete: a. A constructor that accepts a manufacturer and a serial number as its parameter. This constructor performs the following actions: i Store the serial number as a string ii Set a unique id number as an integer(hint- use the nextId). iii Set the IP address to the value “192.168.0.”+idnumber iv Set a local representation of a the power used in mW to the integer 1. v Set the password to “admin”. vi Prints the value “Created ”+ the result of the toString() method after assigning all instance data. vii Increment the number of things on record. b. Accessors for all private variables – Ensure the accessors for id, password and powerUse are named getId(), getPassword() and getPowerUse() c. A method setPassword that accepts a string argument and sets the instance password to the argument. All instance variables, except the password, should be private. The password should be protected. In class SmartHome, method addThing, • Create a…
A stream is a path of communication between the source of some information and its destination. InputStream is an abstract class that defines the fundamental ways in which a destination consumer reads a stream of bytes from some source. Explain the details about the abstract Class InputStream that includes read(), skip(), available(), mark() and reset().
Class 1Final Class2Final Assignment Class1 Midterm 28.75 24.05 15 11 61.25 50.05 15 28 42.5 35.05 13 19 53.75 44.05 20 26 53.75 44.05 20 22 36.25 30.05 18 13 38.75 32.05 20 10 37.5 31.05 10 11 45 37.05 13 16 41.25 34.05 16 15 48.75 40.05 19 16 41.25 34.05 20 16 30 25.05 10 12 45 37.05 12 22 36.25 30.05 10 13 53.75 44.05 15 23 62.5 51.05 12 28 50 41.05 14 20 52.5 43.05 11 20 43.75 36.05 13 15 38.75 32.05 15 10 60 49.05 19 30 52.5 43.05 13 16 46.25 38.05 13 24 50 41.05 18 20 37.5 31.05 10 16 31.25 26.05 20 10 41.25 34.05 11 18 37.5 31.05 12 13 31.25 26.05 14 15 Var=80.55 Var=55.29 Use regression analysis to compute the linear regression equation for the data with the final exam for Class1 as the dependent variable and the scores for on the midterm for Class1 as the independent variable. If someone made a 30 on the midterm in Class1 what would be your estimate of their grade on the final exam in Class1? Be sure and show…
Home B Announcements zy Section 6.2 - IT 14 X B 6-1 Short Answer x O SCS 100 Module X * 6-1 Short Answer x * Upload Documen x + ô https://learn.zybooks.com/zybook/SNHUIT140V3/chapter/6/section/2 = zyBooks My library > IT 140: Introduction to Scripting v3 home > 6.2: List methods E zyBooks catalog Help/FAQ 8 Jose Roque Feedback? CHALLENGE ACTIVITY 6.2.1: Reverse sort of list. Sort short_names in reverse alphabetic order. Sample output with input: 'Jan Sam Ann Joe Tod' ['Tod', 'Sam', 'Joe', 'Jan', 'Ann'] 247772.2002516.qx3zqy7 1 user_input = input() 2 short_names = user_input.split() 1 test 3 passed 4 ' Your solution goes here '" 6 print(short_names) All tests passed 11:45 PM P Type here to search 84°F Clear 8/2/2021 近
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APPLICATION - VLSM: You are a network administrator and you have been assigned the task of setting up the IP network. You have a single class B IP address range 128.64.53.252/16 and have to setup the following networks: • Network V = 1010 hosts • Network E= 8002 hosts Network R = 30600 hosts • Network N = 2 hosts • Network O = 500 hosts Fill in the table: NETWORK (JUST WRITE THE LETTER) V E R N O 255.0 ΝΑ FIP LIP BA
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