7. Consider the following reaction: CH₁ (g) +4 Cl₂ (g) → CCl4 (g) + 4 HCl (g) When 1.65 L Cl₂ (g) at STP reacts with sufficient CH. (g) via the given equation, 7.30 kJ of heat is released. The standard enthalpy of formation for CH. (g) is - 74.8 kJ/mol and that of HCC (g) is-92.3 kJ/mol. Calculate the standard enthalpy of formation for CCl4 (g)? ANSWER: -102 kJ/mol

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Chapter5: Gases
Section: Chapter Questions
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7. Consider the following reaction:
CH4 (g) +4 Cl₂ (g) → CCl4 (g) + 4 HCt (g)
When 1.65 L C₂ (g) at STP reacts with sufficient CH. (g) via the given equation, 7.30 kJ of heat
is released. The standard enthalpy of formation for CH4 (g) is - 74.8 kJ/mol and that of HCt (g)
is-92.3 kJ/mol. Calculate the standard enthalpy of formation for CCl4 (g)?
ANSWER: - 102 kJ/mol
7. Consider the following reaction:
CH4 (g) +4 Cl₂ (g) → CCl4 (g) + 4 HCt (g)
When 1.65 L Cl₂ (g) at STP reacts with sufficient CH4 (g) via the given equation, 7.30 kJ of heat
is released. The standard enthalpy of formation for CH4 (g) is - 74.8 kJ/mol and that of HCl (g)
is-92.3 kJ/mol. Calculate the standard enthalpy of formation for CCl4 (g)?
ANSWER: -102 kJ/mol
Transcribed Image Text:7. Consider the following reaction: CH4 (g) +4 Cl₂ (g) → CCl4 (g) + 4 HCt (g) When 1.65 L C₂ (g) at STP reacts with sufficient CH. (g) via the given equation, 7.30 kJ of heat is released. The standard enthalpy of formation for CH4 (g) is - 74.8 kJ/mol and that of HCt (g) is-92.3 kJ/mol. Calculate the standard enthalpy of formation for CCl4 (g)? ANSWER: - 102 kJ/mol 7. Consider the following reaction: CH4 (g) +4 Cl₂ (g) → CCl4 (g) + 4 HCt (g) When 1.65 L Cl₂ (g) at STP reacts with sufficient CH4 (g) via the given equation, 7.30 kJ of heat is released. The standard enthalpy of formation for CH4 (g) is - 74.8 kJ/mol and that of HCl (g) is-92.3 kJ/mol. Calculate the standard enthalpy of formation for CCl4 (g)? ANSWER: -102 kJ/mol
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