7.- A random sample of 50 consumers taste-tested a heW ShaCk (0: do not like; 1: like; 2: indifferent) and recorded as follows: 10012011000102022001100001020001001001010200110001 Options Frequency table results for varl: Count- 50 varl. Frequency Relative Frequency O.58 lo 15 03 0.12 a) Use an 80% confidence interval to estimate the proportion of consumers who like the snack food. b) Test Ho: p = 0.50 against Ha: p > 0.50, where p is the proportion of customers who do nột like the snack food. Use a = 0.10. Answer: CV = RR = Test statistics = P-value =

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7.- A random sample of 50 consumers taste-tested a new snack food. Their responses were coded
(0: do not like; 1: like; 2: indifferent) and recorded as follows:
10012011000102022001100001020001001001010200110001
Options
Frequency table results for varl:
Count - So
Frequency Relative Frequency.
0.58
varl .
29
15
0.3
0.12
a) Use an 80% confidence interval to estimate the proportion of consumers who like the snack food.
b) Test Ho: p = 0.50 against H3: p > 0.50, where p is the proportion of customers who do nót like the
snack food. Use a = 0.10.
RR =
Test statistics =
P-value =
Answer: CV =
Conclusion: Keep H.
Reject H,
Transcribed Image Text:7.- A random sample of 50 consumers taste-tested a new snack food. Their responses were coded (0: do not like; 1: like; 2: indifferent) and recorded as follows: 10012011000102022001100001020001001001010200110001 Options Frequency table results for varl: Count - So Frequency Relative Frequency. 0.58 varl . 29 15 0.3 0.12 a) Use an 80% confidence interval to estimate the proportion of consumers who like the snack food. b) Test Ho: p = 0.50 against H3: p > 0.50, where p is the proportion of customers who do nót like the snack food. Use a = 0.10. RR = Test statistics = P-value = Answer: CV = Conclusion: Keep H. Reject H,
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