MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Suppose X and Y are two random variables with E[X] = 1, Var (X) = 4, E[Y ] = -1, Var (Y) 4, and Cov (X, Y) = 1. Find the standard deviation of (X - Y). = (a) 2 (b) √2 (c) 6 (d) √6 (e) None of the abovearrow_forwardSuppose that the unknown X is uniformly distributed between 0 and 2. What is the expected value of (4X3 + 1)?arrow_forwardFor a random variable X, suppose that E[X] = 1 and Var(X) = 5. Then %3D (a) E[(2 + X)²] = (b) Var(2 + 3X) = Netsu rtiol orodit on this problemarrow_forward
- 7. A discrete random variable X taking non-negative integer values has probability gen- erating function: 1 rx(t) = (2- t)2 (a) Calculate P(X = 2).arrow_forwardSuppose X is a random variable of uniform distribution between 1 and 7. Find E(X)arrow_forward#2: Suppose a random variable X has expected value E[X] = 3 and variance Var(X) = 4. Compute the following quantities. (a) E[3X + 2] (b) E[X²] (c) E[(3X+2)²] (d) Var[2X + 2]arrow_forward
- Z is the present-value random variable for a whole life insurance of b payable at the moment of death of (x). You are given: (i) (ii) 8 = 0.05 (iii) The net single premium for this insurance is equal to Var(Z). Calculate b. x+t = 0.01 t≥0 (A) 1.36 (B) 1.68 (C) 2.00 (D) 2.32 (E) 2.64arrow_forwardSuppose that a medical test has a 85% chance of detecting a disease if the person has it (P(PT|D)=0.85) and a 90% chance of correctly indicating that the disease is absent if the person really does not have the disease (P(NT|Dc=0.90). Suppose that 95% of the population does not have the disease P(Dc)=0.95 What is the probability that a randomly chosen person will test negative P(NT)?arrow_forward
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