7) Give the reaction type for each of the following reactions. (2 points each) -> a. Pb(OH) 2 (s) → PbO (s) + H2O (1) b. Cl2 (aq) +21¹ (aq) → 2 CI-1 + 12 (aq) (aq) c. HC2H3O2 (aq) + NaOH(aq) → NaC2H3O2 (aq) + H2O (1) Reaction Type

How many moles of NaOH are there if the mass of KHP is 1.253g?

Consider the reaction below: 3 Na2O(aq) + 2 Al(NO3)3(aq) ----> _ Compound A + _ Compound B (OR "3" N a2O(a q) + "2" A l(N O3)3(a q) right arrow Compound A + Compound B) One of the the single ions that would be used to form compound A or compound B would be ____.

What salt is produced in each of the following neutralization reactions? A. HNO3 (aq) + KOH(aq)→H2O(1)+? B. HNO3 (aq) + Ca(OH)2 (aq)→H20(1)+? C. HCl(aq) + Ca(OH)2(aq)→H2O(1)+? D. HCI(aq) + KОн (аq) —HО()+? Drag the appropriate items to their respective bins. • View Available Hint(s) Reset Help | Ca(NO3)2| | KNO; СаCт |кСl | СаCla кс к-NO3 CANO3 Reaction A Reaction B Reaction C Reaction D Not a product

Write net ionic equations for acid-base reactions. Write a net ionic equation for the overall reaction that occurs when aqueous solutions of ascorbic acid (H2C6H606) and sodium hydroxide are combined. Assume excess base. Be sure to specify states such as (aq) or (s). + +

According to this equation how many H2O moles are produced  3 Mg(OH)2 (s) + 2 H3PO4 (aq) → Mg3(PO4)2 (s) + 6 H2O (l) According to this equation how many acid moles, base moles are needed to produce 1.37 moles of K2SO4. And how many moles of water is produced 2 KOH (aq) H2SO4 (aq) → K2SO4 (aq) + 2 H2O (l)

5. Which of the following reactions best represents the hydrolysis reaction of a salt that produces an acidic solution when dissolved in water? Let C and A represent the cation and anion of the salt respectively. a) CA(aq) + H₂O(0) C'(aq) + A (aq) + H₂O(0) AH(aq) + C(aq) + OH (aq) b) CA(aq) + H₂O(0) c) CA(aq) + 2H₂O(0) →COH(aq) + A (aq) +H,O'(aq) - - d) CA(aq) + H₂O(0) →→→→→COH(aq) + HA(aq) Explain your answer:

Identify the correct net ionic equation for the reaction that occurs when solutions of HF and KOH are mixed. Multiple Choice: HF(aq) + OH-(aq) → H2O(l) + F-(aq) HF(aq) + KOH(aq) → H2O(l) + KF(s) H+(aq) + KOH(aq) → H2O(l) + K+(aq) H+(aq) + OH-(aq) → H2O(l) HF(aq) + KOH(s) → H2O(l) + KF(aq)