7: A pipe of constant diameter flowing water (of density pw) horizontally at height h = ho meters has an original pressure Po. The pipe now encounters a segment where it rises to a height of h: hi meters. What is the new pressure Pi in the elevated segment of the pipe? A) P1 = Po B) P1 = Po – (1/2)(pw)(vr)² C) P1 = Po+ (1/2)(pw)(g)(ho + h1) D) P1 = Po – (pw)(g)(hı – ho)

Principles of Physics: A Calculus-Based Text
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Chapter15: Fluid Mechanics
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Problem 20P: A tank with a flat bottom of area A and vertical sides is filled to a depth h with water. The...
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7: A pipe of constant diameter flowing water (of density pw) horizontally at height h = ho meters
has an original pressure Po. The pipe now encounters a segment where it rises to a height of h
hị meters. What is the new pressure Pi in the elevated segment of the pipe?
A) Pi = Po
B) P1 = Po – (1/2)(pw)(vr)²
C) P1 = Po+ (1/2)(pw)(g)(ho + hi)
D) P1 = Po – (pw)(g)(hı – ho)
8: A 10-kg piece of aluminum sits at the bottom of a lake, right next to a 10-kg piece of lead,
which is much denser than aluminum. Which one has the greater buoyant force on it?
A) the lead
B) the aluminum
C) Both have the same buoyant force.
D) It cannot be determined without knowing their volumes.
Transcribed Image Text:7: A pipe of constant diameter flowing water (of density pw) horizontally at height h = ho meters has an original pressure Po. The pipe now encounters a segment where it rises to a height of h hị meters. What is the new pressure Pi in the elevated segment of the pipe? A) Pi = Po B) P1 = Po – (1/2)(pw)(vr)² C) P1 = Po+ (1/2)(pw)(g)(ho + hi) D) P1 = Po – (pw)(g)(hı – ho) 8: A 10-kg piece of aluminum sits at the bottom of a lake, right next to a 10-kg piece of lead, which is much denser than aluminum. Which one has the greater buoyant force on it? A) the lead B) the aluminum C) Both have the same buoyant force. D) It cannot be determined without knowing their volumes.
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