Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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Still on the same question, sorry. I encircled my question. It said there “divide -6 on both sides” but, all I see is -1/-1. Where is 6- in here? Thanks
ll AT&T ? 2:18 PM 1 37% O b) The solution of the equation can be evaluated as following: -7(у - 4) — -у-26 = -7y + 28 —у— 26 = -7y+ 28 + y -у - 26 + у By adding y ( =(-7y+y)+28 (-y+y)-26 = -6y + 28 = 0– 26 = -6y + 28 = - 26 = -6y + 28 – 28 = - 26 – 28 By subtrac = -6y + 0 - 54 = -6y - 54 -бу -54 By dividing - 6 on both -6 -(-), -1×54 V = -1x6 - (쿠),(#) 54 = y = 6 v = 9 This is the required solution
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Transcribed Image Text:ll AT&T ? 2:18 PM 1 37% O b) The solution of the equation can be evaluated as following: -7(у - 4) — -у-26 = -7y + 28 —у— 26 = -7y+ 28 + y -у - 26 + у By adding y ( =(-7y+y)+28 (-y+y)-26 = -6y + 28 = 0– 26 = -6y + 28 = - 26 = -6y + 28 – 28 = - 26 – 28 By subtrac = -6y + 0 - 54 = -6y - 54 -бу -54 By dividing - 6 on both -6 -(-), -1×54 V = -1x6 - (쿠),(#) 54 = y = 6 v = 9 This is the required solution
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(-6)/(-6)=1 that all we know.we just solve it by below method.

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