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6x 29. What is the particular antiderivative of f(x) = whose y-intercept is –4? 1 a. y = 4 ln |x² – 1| – 3 b. y = 4ln |x² – 1|+3 c. y = 3 ln |x² – 1| – 4 d. y = 3 ln |x² – 1|+4

6x 29. What is the particular antiderivative of f(x) = whose y-intercept is –4? 1 a. y = 4 ln |x² – 1| – 3 b. y = 4ln |x² – 1|+3 c. y = 3 ln |x² – 1| – 4 d. y = 3 ln |x² – 1|+4

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.3: Implicit Differentiation
Problem 11E
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7dx determine its particular antiderivative passing through the point of 30. Evaluate 1- x2 origin. 1+x In 7 7 a. y = C. y = In 2 7 1 + 2 In d. y = 2 b. y = In + 7 2 + +|
Transcribed Image Text:7dx determine its particular antiderivative passing through the point of 30. Evaluate 1- x2 origin. 1+x In 7 7 a. y = C. y = In 2 7 1 + 2 In d. y = 2 b. y = In + 7 2 + +|
29. What is the particular antiderivative of f(x) = 6x whose y-intercept is -4? x² – 1 a. y = 4ln |a² – 1| – 3 b. y = 4 ln |x² – 1|+3 c. y = 3 ln |x² – 1| – 4 d. y = 3 ln |a² – 1|+4
Transcribed Image Text:29. What is the particular antiderivative of f(x) = 6x whose y-intercept is -4? x² – 1 a. y = 4ln |a² – 1| – 3 b. y = 4 ln |x² – 1|+3 c. y = 3 ln |x² – 1| – 4 d. y = 3 ln |a² – 1|+4
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