68% of statistics 95% of statistics 99.7% of statistics 4 Mean ▲ Mean 3 st dev 1 st. 1 st. 2 st. dev below 2 st dev above 3 st. dev below above dev dev below above The number of potholes in any given 1-mile stretch of freeway pavement in Pennsylvania has a Normal distribution. This distribution has a mean of 63 potholes, and a standard deviation of 7 potholes. Using the Empirical Rule, what is the approximate percentage of 1-mile long roadways with potholes numbering between 56 potholes and 70 potholes? % 4 Mean

The weight of all cans of coffee has a standard deviation of 0.76 ounces. A sample of 48 cans of coffee is taken study. Which of the following best describes the distribution of x¯?A. The distribution of x¯ is normal becuase it is always normalB. The distribution of x¯ may not be approximately normal because n = 48C. The distribution of x¯ is approximately normal becuase n = 48D. The distribution of x¯ is not normal because the population is normalE. None of the above

A particular fruits weights are normally distributed, with a mean of 797 grams and a standard deviation of 17 grams. The heaviest 16% of fruits weigh more than how many grams?

Length of skateboards in a skateshop are normally distributed with a mean of 32 in and a standard deviation of 0.6 in. The figure below shows the distribution of the length of skateboards in a skateshop. Calculate the shaded area under the curve.

The heights of children ages 3-5 are approximately normally distributed with a mean of 40 inches and a standard deviation of 2.5 inches. What percent of children are between 39 and 42 inches?

Butt-to-knee length is approximately normally distributed with a mean of 23.1 inches and a standard deviation of 1.2.  Theater seats are designed to be comfortable for as many adults as possible.  If the seats are required to fit the middle 80% of the population, the seat must be comfortable for what butt-to-knee length range?

Suppose we know that the aspirin content of aspirin tablets follows a Normal distribution with standard deviation of o= 5 mg.

Consider population data with 5 being the standard deviation, 5 being the mean. Compute an 88.9% chebyshev interval around the population mean