65. A A thin, spherical shell of mass m and radius R rolls down a parabolic path PQR from height H without slipping (assume R

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I want to ask why does the moment of inertia equal to 2/3 mR^2, and how should I answer this problem? Thank you so much !
65. A A thin, spherical shell of mass m and radius R rolls down a
parabolic path PQR from height H without slipping (assume
R<<H) as shown in Figure P13.65. Path PQ is rough (and so
the shell will roll on that path), whereas path QR is smooth, or
frictionless (so the shell will only slide, not roll, in this region).
Determine the height h above point Q reached by the shell on
path QR.
H
P
R
FIGURE P13.65
R
Transcribed Image Text:65. A A thin, spherical shell of mass m and radius R rolls down a parabolic path PQR from height H without slipping (assume R<<H) as shown in Figure P13.65. Path PQ is rough (and so the shell will roll on that path), whereas path QR is smooth, or frictionless (so the shell will only slide, not roll, in this region). Determine the height h above point Q reached by the shell on path QR. H P R FIGURE P13.65 R
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