64 / 30 75 / \ /\ 10 40 70 80 // \ \ 1 38 68 73 90 Answer:
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![Delete the node 64 from the BST given below.
64
1
30
75
/\ / \
10 40 70 80
// \ \
38 68 73 90
1
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- 5.display all integers in a chain of linked nodes a.O(n2) b.O(n) c.O(1) d.O(log n) e.none of these is correctIf there are pointers to both the previous and next node in each node, how can this procedure be completed in O(1) time?in C program, create a linked list that asks the user to insert a single-digit or multi-digit number. Once the number is inserted, your code turns every single digit of the inserted number into a node, and as the output the code prints out the sorted version of these digits that s called a "sorted linked list". Example: input: 5208514 Output: 0124558
- From the below doubly linked list, identify the address of the node B. NULL L Ox257 Ох423 M Ox643 Ox257 N N A B O a. NULL O b. Ox423 O c. Ox643 O d. Ox257Complete the code provided below, so that it : Accepts strings from the user till the user enters "End!", and creates a BST from them with respect to the order of their entry if the user enters "End!" as the first input, then it should: Display "BST needs at least one node, enter a valid input please!" Accepts strings from the user till the user enters "End!" Next, it should display "which node would you pick?", and accept a string (i.e. the key attribute for this Node) from user as an input. Then, display the distance between the given node from the root of the BST. The distance between root and a node can be calculated by the number of edges between them If the string (ie node) is not found then: Your code should display "Not Found!" Then, your code should display: ' Would you like to choose another node? Y/N' If the user enters 'N' end the program, otherwise let the user choose another node and display the distance for the new node. The program should continue…Home Asagnment Write a program that should create a single link list and it should insert and delete nodes from link list. Write an algorithm that should concatenate three link lists into one link list. Write an algorithm that should split a single link list into three link list. Assume that initial link list has 30 nodes. Write an algorithm that should count nodes with even values. Write an algorithm that should sort values of nodes of link list. Write an algorithm that should delete duplicate nodes from link list. Write an algorithm that should delete all nodes from link list. Write an algorithm that should reverse data of all nodes of link list.
- Create a doubly link list with at least 5 nodes, then perform the following operation on that link list. As you perform the operation, write down the algorithm and c++ code too. Show the operations diagrammatically. Traversal Searching SortingImplements the clone_node function that duplicates. If the node has a next it also duplicates it Hint: implement the following recursive pseudocode function clone_node(node) if node is NULL returns NULL returns new_node(node.value, clone_node(node.next)) Complete the code: def clone_node(node): r = <... YOUR CODE HERE ...> return rImplement a __setitem__ function that also supports negative indices. For example: W = L2(Node(10, Node(20, Node(30))))print W[ 10, 20, 30 ] W[1]=25print W[ 10, 25, 30 ] W[-1]=35print W[ 10, 25, 35 ] Complete the code: def L2(*args,**kwargs): class L2_class(L): def __getitem__(self, idx): <... YOUR CODE HERE ...> def __setitem__(self, idx, value): <... YOUR CODE HERE ...> return L2_class(*args,**kwargs) W = L2(Node(10, Node(20, Node(30))))print(W)W[1]=25print(W)W[-1]=35print(W)
- Write C++ Code for Inserting a Node.Index Element 00 25 01 62 02 76 03 471 Considering all the elements and its indexes at the right side: 04 243 05 99 06 07 81 111 Write a sequence of List operations that 08 719 would result to a LIST that contains 09 186 ONLY the elements with its respective indexes: {index[00]=104, index[01]=165, index[02]=115, index[03]=384, index[04]=248, index[05]=117}. 10 66 11 506 12 290 13 359 14 121 15 102 16 818 17 34 18 499 19 620 20 103 21 444 22 904 23 972 24 193code in node Js only
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