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62 In the single-slit diffraction experiment of Fig. 36-4, let the wave- length of the light be 500 nm, the slit width be 6.00 um, and the view- ing screen be at distance D = 4.00 m. Let a y axis extend upward along the viewing screen, with its origin at the center of the diffraction pattern. Also let Ip represent the intensity of the diffracted light at point P at y = 15.0 cm. (a) What is the ratio of Ip to the intensity Im at the center of the pattern? (b) Determine where point P is in the diffraction pattern by giving the maximum and minimum between which it lies, or the two minima between which it lies. Incident wave T a/2 a/2 Į This pair of rays cancel each other at P₁. So do all such pairings. B Totally destructive interference 11 0 Central axis Viewing screen P₁ Po Figure 36-4 Waves from the top points of two zones of width a/2 undergo fully destructive interference at point P₁ on viewing screen C.
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Transcribed Image Text:62 In the single-slit diffraction experiment of Fig. 36-4, let the wave- length of the light be 500 nm, the slit width be 6.00 um, and the view- ing screen be at distance D = 4.00 m. Let a y axis extend upward along the viewing screen, with its origin at the center of the diffraction pattern. Also let Ip represent the intensity of the diffracted light at point P at y = 15.0 cm. (a) What is the ratio of Ip to the intensity Im at the center of the pattern? (b) Determine where point P is in the diffraction pattern by giving the maximum and minimum between which it lies, or the two minima between which it lies. Incident wave T a/2 a/2 Į This pair of rays cancel each other at P₁. So do all such pairings. B Totally destructive interference 11 0 Central axis Viewing screen P₁ Po Figure 36-4 Waves from the top points of two zones of width a/2 undergo fully destructive interference at point P₁ on viewing screen C.
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Step 3: Calculation of angle of diffraction
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Step 4: Calculation of ratio of intensity
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Step 5: Calculation of location of diffraction pattern on screen
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