60° 60° Prob. 11-49

Determine the resultant of forces A and B. The value of A is 87 N and the value of B is 90 N.

B. Determine the concavity and the inflection points of the x² +4 f(x)= function 2x

80 mm, A E -170 mm B D C 125 mm 75 mm Problem 06.085.a - Frame with 2-force member Determine the components of the reactions at A and E if a 930-N force directed vertically downward is applied at B. The components of the reaction at A are: Ax = lb- Ay = lb t The components of the reaction at E are: E₁= lb→

6. A 2-bar truss is as follows. AB= 4 m, BC=5 m, AC=3 m. The black block on C is a friction plate. When the friction coefficient is greater than u, the truss is stable. Determine the value of μ. A P B Hint: First, determine the internal force of AB and BC bar by Joint method at Joint B, Second determine Cx, Cy by Joint method at Joint C; then determine the value of µ.

Engineering statics

Determine the variation in the width w as a function of x for the cantilevered beam that supports a concentrated force P at its end so that it has a maximum bending stress sallow throughout its length. The beam has aconstant thickness t.

From the following armor, determine the following: Reactions in A and F. The internal forces at node C. (Indicate whether the forces are in compression or tension.)  The internal forces in the elements CH, CD and HI. (Indicate if the forces are in compression (C) or tension (T)). Draw the respective free-body diagrams. Consider the following:  A and F are supports. the angles a, B, y are angles of 90, 60 and 30 ° respectively (Check image pr2 for the image of the armor) (Check image pr2.2 for the values to be used)

Take A = 150 mm^2 and E = 200 GPa

Six forces are acting on the wedge-shaped block as shown. It is known that F₁ = F₁ F₂ = F₂ = 400 kN, F3 = F₂ = 600 kN, a = 10 m and b = 8 m. The six forces form three couples. Determine the resultant couple. (1). M = 4800kN-m (†) (3). M = 8264kN-m (†) F₁ 30⁰ a (2). M = 4800kN-m (↓) (4). M = 8264kN·m (↓) = 200 KN, F₂