Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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6.2.40 help!

338 Chapter 6 First- and Second-Order Transient Circuits 6.2.40 Use the step-by-step method to find vo(t) for t> 0 in the 6.2.44 Find i(t) for t> 0 in the circuit in Fig. P6.2.44 using the aupin circuit in Fig. P6.2.40.0 <1 step-by-step method. 12 02 VO 4 Ω 4V+ HELS O erit ni 0 t=0 VST 2 ΚΩ bezolo nood orT ve.s.a FIGURE P6.2.40 0 <1101 21 brip smil gnols tot 6.2.41 Use the step-by-step method to find vo(t) for t> 0 in the 101 (1)) bofl circuit in Fig. P6.2.41.hr find 6Ω DYS t=0 4Ω 12 V ww Ova oto nt=0 6 V VS4 A 4 H + v (1) S.09 AUDI 2 ΚΩ 50 μF O + 2 H TE39 BAUDR FIGURE P6.2.41 yd-gota 04 pili nowion 6.2.42 Use the step-by-step method to find vo(t) for t> 0 in the circuit in Fig. P6.2.42. 1 ΚΩ vo(t) 1 ΚΩ FIGURE P6.2.42 0431031 3 Ω OLE HE eε.s. ma 100 μF Ht 3 Ω 1 ΚΩ 6.2.43 Find vo(t) for t> 0 in the network in Fig. P6.2.43 using en ar 0. mi qo12-10-go the step-by-step method. ec. X +24 V • 2 ΚΩ POT2.27 4A 05 A FIGURE P6.2.43 ww ww + vo(t) t = 0 + vo(t) gia ni jinolo 32 ΚΩ ONA KOE 402 VaE +12 V BE.S.O V sr 105 V (+ 00 12 ΚΩ 101 (1) ub 12 V (+ 6 ΚΩ 12 V (+ OIS 10 ΩΣ dosor 6023 FIGURE P6.2.44 6.2.45 Use the step-by-step method to find vo(t) for t> 0 in the circuit in Fig. P6.2.45. EE. i(t) PESO 1H BAUDR t=0 3 ΚΩ ww 100 μF 15 Q2 2014 652 DE BA t = 0 6 ΚΩ 101 (1) senog291 solg 2 kg 2 ΚΩ srij gnizolo ww FIGURE P6.2.45 6 ΚΩ 100 μF sisub sdi sal EE S १८ 3 ΚΩ 7 000 6.2.46 Use the step-by-step method to find vo(t) for t> 0 in the circuit in Fig. P6.2.46. 2.3115 ope 14001 FIGURE P6.2.46 28.5.893AUDI $10 t=0 ΣΕΚΩ Lon + desorgssuplebas blocb seu a.s.a ipoodini 0<1 pdrm (%(t) -O DAS v (1) va
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Transcribed Image Text:338 Chapter 6 First- and Second-Order Transient Circuits 6.2.40 Use the step-by-step method to find vo(t) for t> 0 in the 6.2.44 Find i(t) for t> 0 in the circuit in Fig. P6.2.44 using the aupin circuit in Fig. P6.2.40.0 <1 step-by-step method. 12 02 VO 4 Ω 4V+ HELS O erit ni 0 t=0 VST 2 ΚΩ bezolo nood orT ve.s.a FIGURE P6.2.40 0 <1101 21 brip smil gnols tot 6.2.41 Use the step-by-step method to find vo(t) for t> 0 in the 101 (1)) bofl circuit in Fig. P6.2.41.hr find 6Ω DYS t=0 4Ω 12 V ww Ova oto nt=0 6 V VS4 A 4 H + v (1) S.09 AUDI 2 ΚΩ 50 μF O + 2 H TE39 BAUDR FIGURE P6.2.41 yd-gota 04 pili nowion 6.2.42 Use the step-by-step method to find vo(t) for t> 0 in the circuit in Fig. P6.2.42. 1 ΚΩ vo(t) 1 ΚΩ FIGURE P6.2.42 0431031 3 Ω OLE HE eε.s. ma 100 μF Ht 3 Ω 1 ΚΩ 6.2.43 Find vo(t) for t> 0 in the network in Fig. P6.2.43 using en ar 0. mi qo12-10-go the step-by-step method. ec. X +24 V • 2 ΚΩ POT2.27 4A 05 A FIGURE P6.2.43 ww ww + vo(t) t = 0 + vo(t) gia ni jinolo 32 ΚΩ ONA KOE 402 VaE +12 V BE.S.O V sr 105 V (+ 00 12 ΚΩ 101 (1) ub 12 V (+ 6 ΚΩ 12 V (+ OIS 10 ΩΣ dosor 6023 FIGURE P6.2.44 6.2.45 Use the step-by-step method to find vo(t) for t> 0 in the circuit in Fig. P6.2.45. EE. i(t) PESO 1H BAUDR t=0 3 ΚΩ ww 100 μF 15 Q2 2014 652 DE BA t = 0 6 ΚΩ 101 (1) senog291 solg 2 kg 2 ΚΩ srij gnizolo ww FIGURE P6.2.45 6 ΚΩ 100 μF sisub sdi sal EE S १८ 3 ΚΩ 7 000 6.2.46 Use the step-by-step method to find vo(t) for t> 0 in the circuit in Fig. P6.2.46. 2.3115 ope 14001 FIGURE P6.2.46 28.5.893AUDI $10 t=0 ΣΕΚΩ Lon + desorgssuplebas blocb seu a.s.a ipoodini 0<1 pdrm (%(t) -O DAS v (1) va
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