6.00 με 150 μ.. -2.00 μ. 3.00 cm - 2.00 cm Figure P15.10 Problems 10 and 18.

Two point charges of mass m each are suspended in the gravitational field of the Earth by two non-conducting massless strings, each of length 1, attached to the same fixed point. The spheres are given equal charges of the same sign. As a result each string makes angle a to the vertical (see figure below). Write down an expression for the tension of a string Tin terms of Coulomb force Fc between the charges and the angle a. Use the following notation (without the quotes): "/" for division, "*" for multiplication, "+" an "-" as usual. For powers used "^2", while for square root use "sqrt". To indicate that square root applies to the whole expression use brackets - for example, for √AB use sqrt(A*B). For Greek letters such as , a etc. use pi, alpha. For example to get √AB use 1/pi*A^2/B*sqrt(AB). Please use the exact variables given in the conditions of the problem: e.g 1 if L is given, then do not use 1. For subscripts such as Fe simply write "FC" (without the quotes). Please use…

Two point charges of mass m each are suspended in the gravitational field of the Earth by two non-conducting massless strings, each of length 1, attached to the same fixed point. The spheres are given equal charges Q of the same sign. As a result each string makes angle a to the vertical (see figure below). Calculate m, if 1 = 76.4 cm, Q = 4 μC and α = л/6. Take Coulomb constant ke =8.99×10° N m² C-2. Give your answer in grams. Answer: d D M M Q 60 g

please help with questions 28,29,30