**Question:**6. The electric field amplitude of the signal at that point is 0.780 V/m. What is the amplitude of the magnetic field of the signal at that point?a) 2.6 nT b) 2.1 nT c) 1.6 nT d) 3.1 nT e) 3.6 nT **Explanation:**To find the magnetic field amplitude, we can use the relationship between the electric field (E) and the magnetic field (B) in an electromagnetic wave, which is given by the equation:\[ B = \frac{E}{c} \]where \( c \) is the speed of light in a vacuum (\( c \approx 3 \times 10^8 \, \text{m/s} \)).Given:- Electric field amplitude (\( E \)) = 0.780 V/mTherefore:\[ B = \frac{0.780 \, \text{V/m}}{3 \times 10^8 \, \text{m/s}} \approx 2.6 \times 10^{-9} \, \text{T} = 2.6 \, \text{nT} \]Hence, the correct answer is (a) 2.6 nT.

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Answered: 6. The electric field amplitude of the…

6. The electric field amplitude of the signal at that point is 0.780 V/m. What is the amplitude of the magnetic field of the signal at that point? a) 2.6 nT b) 2.1 nT c) 1.6 nT d) 3.1 nT e) 3.6 nT

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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