6. Bob draws a simple random sample from an extremely large population of lemons. The sample size is n = 700 and in the sample 250 lemons turn out to be good and 450 lemons turn out to be bad. Find the 95% confidence interval for the population proportion p of good lemons. A. (0.30165, 0.37264) В. (0.31165, 0.38264) C (0 32165 0 39264) D (0 33165 0 40264)

6. Bob draws a simple random sample from an extremely large population of lemons. The sample size is n = 700 and in the sample 250 lemons turn out to be good and 450 lemons turn out to be bad. Find the 95% confidence interval for the population proportion p of good lemons. A. (0.30165, 0.37264) В. (0.31165, 0.38264) C (0 32165 0 39264) D (0 33165 0 40264)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A population of values is normally distributed with μ=58.8 and σ=24.3a) Find P61 for a single randomly selected value. This answer represents the score separating the bottom 61% scores from the top 39% scores. P61 = b) Now draw a random sample of size n=180 . Find P61 for the sampling distribution. This answer represents the score separating the bottom 61% of the sample means from the top 39% of the sample means. P61 = Enter your answers as numbers accurate to 1 decimal place.
Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distributions are relatively normal. Test Ho : HA = Ha VS H. : HA # Hg using the fact that Group A has 8 cases with a mean of 125 and a standard deviation of 18 while Group B has 15 cases with a mean of 118 and a standard deviation of 14. (a) Give the test statistic and thep-value. Round your answer for the test statistic to two decimal places and your answer for the p- value to three decimal places. test statistic = p-value = eTextbook and Media (b) What is the conclusion of the test? Test at a 10% level. O Reject Ho. O Do not reject Ho. eTextbook and Media
Q2: Let x1,X2, . , Xn and y1, y2, ..., Ym represent two independent random samples from the respective normal distributions N(H1,07) and N (H2, 03). It is given that of = 30, but ožis unknown. Then 1. A random variable that can be used to find a 95% confidence interval for - is (x- y) - (H1 - H2) А. ns3 + ms n+m. 3(n+m-2)"tm, nm O A (x – y) – (41 – H2) В. ns? + ms; n + m. (n + m – - 2) пт (x – y) – (41 - H2) С. ns3 + mS;_n+3 3(n+ m-2) ("+3m nm Ос
#11 A sample of 2,018 American adults was asked how they viewed China, with 13% of respondents calling the country "unfriendly" and 9% of respondents indicating the country was "an enemy". Construct a 95% confidence interval of the proportion of American adults who viewed China as either "unfriendly" or "an enemy." Multiple Choice [0.2049, 0.2351] [0.1916, 0.2484] [0.2111, 0.2289] [0.2019, 0.2381]
H. Let X1,..., X, be a random sample from some distribution with unknown u. It's known that X 100 and X = 1783. %3D %3D (40) Supposen = 144 and o? = 12. The value of a, corresponding to the confidence interval [0.7, 1.3] is (a) 0.212 (b) 0.122 (c) 0.050 (d) 0.298
Suppose we have two normal populations denoted A and B, and we want to compare their population variances by estimating the ratio: variance of population B divided by variance of population A. We have an independent random sample of size 15 from population A and an independent random sample of size 9 from population B. The sample variance for population B turns out to be 30 percent larger than that for population A. What is the 99 percent confidence interval for the ratio: population variance of population B divided by population variance of population A? Use stattrek.org for finding the needed critical values.
If n=16, ¯xx¯(x-bar)=35, and s=17, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. I used the formula 35-NORM.INV(1-2.0/2,0,1)*((17)/SQRT(16)) for the lower and the same but with a plus sign for the upper, I got it wrong and dont understand why. We have to use Excel so please explain what excel formula to use.
(Mathematical Statistics) Let X1,X2,...,X5 be a random sample of the Gamma distribution with parameters a = and ß = 0, e > 0. Determine the 95% confidence interval for the parameter e based on the statistic E(i=1 - 5) Xi. 2
7. What is the 95% confidence interval for the difference in the population means, µ1 - µ2, given the data from the two independent samples: n1 =56, x1= 58.2, s1= 4.3, n2=45, x2=60.2, s2=5.5 B. [-3.28 , -0.72] C. [-3.60, -0.40] D. [-3.65 , -0.35] A. [-3.96 , -0.04] 8. What is the 98% confidence interval for the difference in the population means, µ1 - µ2, given: n1= 22, x1= 41.4, s1= 5.9, n2= 19, x2= 43.2, s2= 6.5 D. [-3.48 , -0.12] B. [-3.07 , -0.53] A. [-3.12, -0.48] C. [-3.18, -0.42]
12. Two independent samples are taken from two populations. Sample 1 has a mean of 12.8, a standard deviation of 2.3, and a sample size of 18. Sample 2 has a mean of 14.2, a standard deviation of 5.2, and a sample size of 23. This gives a standard error se(Ã1 — Ă2) = 1.212. A 95% confidence interval for the difference between the two means is: (A) (-2.00, -0.80). (B) (11.66, 13.94). (C) (-3.96, 1.16). (D) (-3.85, 1.05). (E) (-3.78, 0.98).
A researcher selects a random sample of 58 mice from her laboratory. For each mouse, she records the weight of the mouse in grams and whether the mouse prefers Brand A or Brand B food. She would like to know if there is convincing evidence that mouse weight is associated with food preference. Let = 0.10. The observed and expected counts are displayed in the tables. Observed counts: Expected counts: Which of the following contributed the most to the value of the χ2 statistic? average weight and Brand A average weight and Brand B not average weight and Brand A not average weight and Brand B