6. AREAadjustedDPD. -In thelatitudesaccompanyingand adjusted. departurestabulations are theofBYtwotra-verses.ADJUSTED LATITUDE ADJUSTED DEPARTURELINE+N-S+E420.75713.84296.08693.05CD894.37405.36DE50 1.25926.54386.42884,53EF695.04F.A190.67Sums+1691.70-169 1.701812.2518.12.25ADJUSTED LATITUDEADJUSTED DEPARTURECOURSE+N+E1- 2299.30295.582- 3338. 05223.563 - 424.52245. 774- 55 66 - 18.05381.36230.52463.09626. 1 1309. 87Sums+949.93- 949.93+ 772.96-772.96By employing the double parallel distance methoa, determinePROBLEMSETS563'A BCDEE

6. AREA adjusted DPD. In the •latitudes accompanying and adjusted. departures tabulations are the of BY two tra- verses. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S +E -W AB 420.75 713.84 296.08 693.05 894.37 405.36 DE 50 1.25 926.54 386.42 884.53 EF 695.04 F.A 190.67 Sums +1691.70 F169 1.70 1812.25 1812.25 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N +E -W 1- 2 299.30 295.58 2-3 338.05 223.56 3- 4 4 - 5 5 - 6 6 - 1 24.52 245.77 381.36 8.05 230.52 463.09 626.11 309. 87 Sums +949.93 - 949.93 + 772.96 -772.96 MCDE PA a C DEE

6. AREA adjusted DPD. In the •latitudes accompanying and adjusted. departures tabulations are the of BY two tra- verses. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S +E -W AB 420.75 713.84 296.08 693.05 894.37 405.36 DE 50 1.25 926.54 386.42 884.53 EF 695.04 F.A 190.67 Sums +1691.70 F169 1.70 1812.25 1812.25 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N +E -W 1- 2 299.30 295.58 2-3 338.05 223.56 3- 4 4 - 5 5 - 6 6 - 1 24.52 245.77 381.36 8.05 230.52 463.09 626.11 309. 87 Sums +949.93 - 949.93 + 772.96 -772.96 MCDE PA a C DEE

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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TOPOGRAPHYSORT OUT Linear errorPrecisionExterior angles at each of the stationsChainedPolygon area
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The calcula te Based and lengths shown, On The bearing and lantude departure, linear micclosure Of the traverre, If all station s have 0,953 angle and Pre cicion correction NCY? 104 35' G10, 45 10. o00 NCY) 10,000 ES 30¢'54' 6 47,02 sian'on Bea ing lLength 26°10' 04° 35' l ar 30' 358°18' 306°4! A 285.10 G10.45 720,48 203.00 E 69 7.02 195 30 358 18 203 .00
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AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S AB 7i5.20 1200.53 вс CD DE 401.78 414.29 1735.58 419.88 1606.43 456.66 200.70 EF 617.59 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N -S +E - w 281.06 1-2 2-3 281.28 168.75 449.32 337.56 281.22 T12,50 450.66 450.03 225.08 450.06 335.86 Sums +900.09 m 900.09 m+1011.60mHio11.6Om N3456- -2345
Given the following adjusted technical description, solve the AREA using Double Parallel Distance DPD Method. (Strictly round off to 2 dec places) Course Adj Lat Adj Dep DPD 2A -68.99 67.12 ? AB BC -58.07 -52.00 CD 69.92 -97.22 ? DA 57.14 82.10 SUM AREA
Latitude and Departure Given the observed data of a closed traverse, determine the latitudes and departures of each line. Line Length Bearing AB 427.000 m N 59°33’ E BC 301.950 m S 39°18’ E CD 445.660 m S 06°35’ W DE 326.730 m N 17°48’W EA 434.500 m N 70°59’ W * Indicate the sign for latitude and departure * Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
fundamentals of surveying. transit rule.
Compute the Area using the DMD and check by DPD method ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N +E W AB 552.45 212.63 BC 232.06 396.50 CD 359.70 283.15 DE 209.37 366.89 EA 215.44 525.39 Sume 784.51m-784.5 1m+892.28m-892.28m (NL) (SL) (ED) (WD)
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What will be the value of DMD for B if DMD for A is -22.87, departures for A and B will be -22.87, +89.24 respectively? O a. 22.8 O b. 43.5 O c. -43.5 O d. -22.8