6. 2 H,S + 3 0, → 2 SO, + 2 H,0 You mix 4.8 mol of hydrogen sulfide with 3.9 mol of oxygen. В A e. What is the limiting reactant? f. How much excess remains? g. What is the theoretical yield of sulfur dioxide? h. If you actually made 2.2 mols of sulfur dioxide, what is the percent yield?

Report Pages DATA Trial A Trial B Trial C Mass of test tube and boiling chip VLT0T 18.491 18.544 Mass of test tube, boiling chip, and reactant (NaHCO3) 18. 702 18&917 Mass of test tube, boiling chip, and product (NaCl) 17.883 18.722 18.892 Mass of test tube, boiling chip, and product (NaCl) AFTER repeated heating 7.879 18.619 18.775. CALCULATIONS SUMMARY (Work should be shown on the next page.) Trial A Trial B Trial C Mass of reactant (NaHCO3) Moles of reactant (NaHCO3) Mass of product (NaCl) Moles of product (NaCl) Ratio of moles NaCl to moles of reactant Average mole-to-mole ratio from trials A B and C T&121 La

Please don't provide hand writtin solution...

a small amount of marble chips (CaCO3) are placed inside a flask and weighed (as seen in #1 above). Nitric acid (HNO3) is added with a buret causing a reaction to occur (as seen in 2&3 above). After the reaction ends, the liquid is drained away, the remaining chips rinsed and dried (seen in #4 above). The data collected is as follows: * Mass of flask with chips before reaction: 120.15 g * Mass of flask with chips after reaction: 112.88 g * Buret reading before acid is added: 47.07 mL * Buret reading after acid is added: 22.70 mL Use the above data to determine the molarity of the nitric acid (HNO3) if the equation for the reaction is: 2HNO3(aq)  +  CaCO3(s)  →   H2O(l)  +  CO2(g)  +  Ca(NO3)2(aq) (round your final answer to 2 decimal places)