6 The reaction of HCI with 1-pentene produces only one product, 2-chloropentane. Why does this product form instead of 1-chloropentane? A. H+ and Cl- know what the "EL-NM" rule is and dutifully comply with it. B. H+ bonds to the C-1 alkene carbon in the first step, forming the more stable carbocation, with (+) charge on C-2, followed by bonding of Cl nucleophile to positively charged C-2. C. There is less steric hindrance if Cl binds to C-2 and H+ bonds to C-1. D. Cl- bonds to the C-2 alkene carbon in the first step, forming the more stable carbon anion with (-) charge on C-1, followed by bonding of H* electrophile to (-) charged C-1.

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6
The reaction of HCI with 1-pentene produces only one product,
2-chloropentane. Why does this product form instead of
1-chloropentane?
A.
H+ and C¹- know what the "EL-NM" rule is and dutifully
comply with it.
B. H+ bonds to the C-1 alkene carbon in the first step, forming
the more stable carbocation, with (+) charge on C-2,
followed by bonding of Cl nucleophile to positively charged
C-2.
C. There is less steric hindrance if Cl- binds to C-2 and H*
bonds to C-1.
D. Cl- bonds to the C-2 alkene carbon in the first step, forming
the more stable carbon anion with (-) charge on C-1,
followed by bonding of H* electrophile to (-) charged C-1.
Transcribed Image Text:6 The reaction of HCI with 1-pentene produces only one product, 2-chloropentane. Why does this product form instead of 1-chloropentane? A. H+ and C¹- know what the "EL-NM" rule is and dutifully comply with it. B. H+ bonds to the C-1 alkene carbon in the first step, forming the more stable carbocation, with (+) charge on C-2, followed by bonding of Cl nucleophile to positively charged C-2. C. There is less steric hindrance if Cl- binds to C-2 and H* bonds to C-1. D. Cl- bonds to the C-2 alkene carbon in the first step, forming the more stable carbon anion with (-) charge on C-1, followed by bonding of H* electrophile to (-) charged C-1.
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