6 *Note: Picture not drawn to scale. What is the approximate area of the shaded region if X = 8 feet and Y= 6 feet? O A. 46.8 feet? ОВ. 33.9 feet? OC. 19.7 feet? OD. 28 3 feet2

Q: 8. Find the area of the shaded region. 150" 8 ft

A:

Q: 1. P 24 QR OR = SR = %3D 10 = ÕS PR = %3D QT =

A: Explanation of the answer is as follows

Q: 3. ind the area of the shaded region. 36 ft 30 ft 23 ft 15 ft 104 ft

A: Area of shaded region is 735 square feet

Q: 9. Find the area shaded. 3 m 6 m 5 m 7 m

A: Given,  AB=3 cm, BC=6 cm, AF= 5 cm, ED= 7 cm

Q: 26 ft 12 ft, 5 ft What is the area of the figure? 13 ft

A: Given,            The figure is shown below :           To find : The area of the figure.

Q: B. Find the area of the composite figure. 260 Ft2 12 ft 20 ft 468 ft2 13 ft 500 ft2 480 ft2 12 ft…

A:

Q: 4. What is the area of the rectangle shown below, in square feet? 12 ft 8 ft

A: The area of rectangle is given by the formula  A=length×width

Q: Find the area. 4 in 5.9 in

A: Given,

Q: 10.2 yd 11.4 yd 11 yd 4 yd

A:

Q: Give the boundaries of the indicated valve 6.1 yards

A:

Q: not d 8 cm scale 12 cm 5 cm 15 cm

A: In order to find the area of the figure; it has to be divided into two regions whose geometrical…

Q: (6) Jo 34 Area = 16m anti

A:

Q: PROBLEM SOLVING: Find the area corresponds to given value of z. 1. Z = 2.74 2. Z = 2.88 3. Z = 3.02

A: Given that  Z follows the standard normal distribution with a mean of zero and a standard deviation…

Q: 1.5 in 4 in

A: In this question we use the formula .... Area of triangle =base*hight /2

Q: Find the area of the shaded region. Round your answer to the nearest tenth (one decimal place). Do…

A: Given, Inner circle with diameter 10 ft  Outer circle with diameter = 10+2+2  ft…

Q: 1. Find the area of the figure below. y 4 -4 -2 2. 4 R.

A: The given figure is parallelogram,

Q: 15. Find the surface area. Use 3.14 for Round to the nearest hundredth. 94 yd --- 73 yd O…

A: CONCEPT:  In a cylinder  Total surface area = curved surface area + lateral surface area. C.S.A. =…