Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Arrange the steps in the correct order to prove that a simple graph T is a tree if and only if it is connected, but the deletion of any of its edges produces a graph that is not connected. (First, prove that if a simple graph T
is a tree, then it is connected and the deletion of any of its edges produces a graph that is not connected, and then prove the converse of it.)
Rank the options below.
Now, Twith {x,y) deleted has no path from x to y, since there was only one simple path from x to y in T, and the edge itself was it. Therefore, the graph with (x, y) deleted is not connected.
Suppose that a simple connected graph 7 satisfies the condition that the removal of any edge will disconnect it.
If T is not a tree, then it has a simple circuit, say, X₁, X2, ..., X₁, X1.
If we delete the edge [xr, x₁) from T, then the graph will remain connected, since wherever the deleted edge was used in forming paths between vertices we can instead use the rest of the
circuit x₁, x2, ..., Xr or its reverse.
Let {x, y) be an edge of Tsuch that x #y.
This is a contradiction to the condition. Therefore, our assumption was wrong, and T is a tree.
Suppose that T is a tree; then, by definition, it is connected.
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Transcribed Image Text:6 Arrange the steps in the correct order to prove that a simple graph T is a tree if and only if it is connected, but the deletion of any of its edges produces a graph that is not connected. (First, prove that if a simple graph T is a tree, then it is connected and the deletion of any of its edges produces a graph that is not connected, and then prove the converse of it.) Rank the options below. Now, Twith {x,y) deleted has no path from x to y, since there was only one simple path from x to y in T, and the edge itself was it. Therefore, the graph with (x, y) deleted is not connected. Suppose that a simple connected graph 7 satisfies the condition that the removal of any edge will disconnect it. If T is not a tree, then it has a simple circuit, say, X₁, X2, ..., X₁, X1. If we delete the edge [xr, x₁) from T, then the graph will remain connected, since wherever the deleted edge was used in forming paths between vertices we can instead use the rest of the circuit x₁, x2, ..., Xr or its reverse. Let {x, y) be an edge of Tsuch that x #y. This is a contradiction to the condition. Therefore, our assumption was wrong, and T is a tree. Suppose that T is a tree; then, by definition, it is connected.
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