(5+4i)(17 – 13i) – (5 + 3i)(17 – 13i)

Q: V-25+ 2iº5+3(i6)' + |9 + 8i| – 4(5+ 6i) v-36

A:

Q: (4/5 - s)2/3 +1) b)

A:

Q: (2) Expand and simplify: (2e³+e-3x)2 Check your answer by substituting x = 0 into this expression…

A:

Q: x3 f) x2+2x+1

A:

Q: Lin says, "I started inside the parentheses and ended up with 23x." 8 – 3(4 – 9x) 8 – 3(-5x) 8 + 15x…

A: Solving this type of questions we have to follow the bodmas rule and we can subtract terms…

Q: Char(2Z/6z) is :

A: Characteristic of a ring R is n if for any x belongs to R n*x=0

Q: 4-L { X.e is equal to: 40320 40320 40320 P+3)8), (p+3) 9) ,-3 (p-3) 9

A:

Q: 4. (Complex Numbers: Basic Operations). Evaluate: 2 – 3i (i) (2 – i) · (1 – 3i); (ii) 3 - i + (2 –…

A: Given- (1) 2-i·1-3i (2)  2-3i3-i+2-3i2 To Find- The value of the above complex number.

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.