Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Discrete math. Q49 is an example, and my question is Q54.

Theorem 2.1.1 Logical Equivalences
Given any statement variables p, q, and r, a tautology t and a contradiction c, the following logical equivalences
hold.
1. Commutative laws:
p^q = q ^p
(p ^ q) ^ r = p ^ (q ^ r)
p^(qv r) = (p ^ q) v (p ^ r)
p^t =p
pv q = q Vp
(p V q) V r = p V (q v r)
p V (q ^ r) = (p v q) ^ (p V r)
2. Associative laws:
3. Distributive laws:
4. Identity laws:
p V c = p
5. Negation laws:
6. Double negative law:
pV ~p = t
~(~p) = p
p^ ~p = c
7. Idempotent laws:
p^p =p
p V p =p
8. Universal bound laws:
p^c = c
~(p V q) = ~p ^~q
p^ (p V q) = p
pvt=t
9. De Morgan's laws:
~(p ^ q) = ~p v~q
10. Absorption laws:
pV (p ^q) = p
11. Negations of t and c:
~t = c
~c = t
expand button
Transcribed Image Text:Theorem 2.1.1 Logical Equivalences Given any statement variables p, q, and r, a tautology t and a contradiction c, the following logical equivalences hold. 1. Commutative laws: p^q = q ^p (p ^ q) ^ r = p ^ (q ^ r) p^(qv r) = (p ^ q) v (p ^ r) p^t =p pv q = q Vp (p V q) V r = p V (q v r) p V (q ^ r) = (p v q) ^ (p V r) 2. Associative laws: 3. Distributive laws: 4. Identity laws: p V c = p 5. Negation laws: 6. Double negative law: pV ~p = t ~(~p) = p p^ ~p = c 7. Idempotent laws: p^p =p p V p =p 8. Universal bound laws: p^c = c ~(p V q) = ~p ^~q p^ (p V q) = p pvt=t 9. De Morgan's laws: ~(p ^ q) = ~p v~q 10. Absorption laws: pV (p ^q) = p 11. Negations of t and c: ~t = c ~c = t
49. (p V ~q) ^ (~pV ~q)
=(~q v p) ^ (~q v~p)
q V (p ^~p)
by (a)
by (b)
by (c)
by (d)
Therefore, (p V ~q) ^ (~p V ~q) = ~q.
= ~q V ¢
= ~9
Use Theorem 2.1.1 to verify the logical equivalences in
50-54. Supply a reason for each step.
50. (р^~q) vр %3Dр
51. р ^ (~gvр) %—D р
52. ~(p V ~q) V (~p ^~q) = ~p
53. ~((~p ^q) Vv(~p^~q)) V (p ^q) = p
54. (р^ (~(~pvq)) V (р^q) — р
expand button
Transcribed Image Text:49. (p V ~q) ^ (~pV ~q) =(~q v p) ^ (~q v~p) q V (p ^~p) by (a) by (b) by (c) by (d) Therefore, (p V ~q) ^ (~p V ~q) = ~q. = ~q V ¢ = ~9 Use Theorem 2.1.1 to verify the logical equivalences in 50-54. Supply a reason for each step. 50. (р^~q) vр %3Dр 51. р ^ (~gvр) %—D р 52. ~(p V ~q) V (~p ^~q) = ~p 53. ~((~p ^q) Vv(~p^~q)) V (p ^q) = p 54. (р^ (~(~pvq)) V (р^q) — р
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