53&cmid%3D11610 es This course A 240-V, 100 A armature full-load line current, 1500 RPM, cumulatively-compounded DC motor is considered in this problem. Its characteristics are given below: RA+Rs = 0.202 RF= 140 2 Radj = 160 2 NF =2000 turns NSE= 16 turns This motor has compensating windings and interpoles. The magnetization curve for this motor at 1500 RPM is shown in a tabular form below 0. 0.1 0.2 0.4 0.5 0.6 0.8 1.0 1.2 1.6 1.8 2.0 2.2 2.4 If,A EA.V 6.0 25 50 110 135 160 205 235 255 275 285 288 290 291 What is the full-load speed of this motor? Select one: a. Full-load speed n = 1875 RPM b. Full-load speed n = 1200 RPM OC. Full-load speed n = 1610 RPM d. None

8) A 230 V fed single quadrant chopper has a 40% duty cycle. A separately excited DC motor is controlled by a chopper. Motor has a back emf constant of 0.5 V/rad/s and 2 22 armature resistance. Determine the torque of motor at speed of 1400 rpm 4.7 N-m 15.44 N-m 10.5 N-m 19 N-m

one hour u have answer please

A value of magnetizing current in a 3-phase induction motor * gives power factor smaller .. larger smaller. .poor large . better O large...poor O

A 100-V series motor is used to drive a load through a pulley. This machine has anarmature resistance of 0.2 ohm and a series-field resistance of 0.25 ohm. When atorque of 25 N-m is applied to the pulley, the speed is 600 rpm. If SPL at this load is300 W, calculate the armature current.

QUESTION 2 a) Draw the equivalent circuit and torque-speed characteristic curve for a series DC motor. b) Briefly explain the induced torque occurs in a series DC motor. e) A 20-hp 240-V 76-A 900 rimin series motor has a field winding of 33 turns per pole. Its armature resistance is 0.09 2, and its field resistance is 0.06 2. The magnetization curve expressed in terms of magnetomotive force versus Ex at 900 rimin is given by the following table: Table Q2 c): The magnetomotive force table for a de motor taken at 900r'min E. V 95 150 188 212 229 243 F.A tuus 1000 1500 2000 2500 500 3000 If the motor running at 33 percent of the full-koad armature current, determine: ) The motor's power converted from electrical to mechanical form, Prene i) The motor's torque, Tnit ii) The motor's speed, n

. Explain how the pulsating mmf of a single-phase induction motor may be considered equivalent to two oppositely-rotating fields. Develop an expression for the torque of the motor. A 125-W, 4-pole, 110-V, 50-Hz single-phase induction motor has the no-load rotational loss of 25 watts and total rotor copper loss at rated load of 25 watts at a slip of 0.06. At a slip s = 0.06, what is the power input to the machine ?

Question 3: Answer the following question below: a. Consider a permanent-magnet de motor with the following parameters: R-0.4ohm, L.-1 mH, kE-0.4 V/(rad/s), kr=0.4 Nm/A, and J-0.03 kg m. The rated torque of this motor is 5 Nm. Plot the steady state torque-speed characteristics for V.-60 V b. The motor in (a) is driving a load whose torque requirement remains constant at 5 Nm, independent of speed. Calculate the armature voltage V. to be applied in steady state, if this load is to be driven at 1,800 rpm. c. In an ECM drive, kg-kr-0.8 in SI units. Plot the phase currents and the induced-emf waveforms, as a function of 5, if the motor is operating at a speed of 150 rad/s and delivering a torque of 7 Nm.

200 +21. If maximum torque of an induction motor is kg-m at a slip of 12%, the torque at 6% slip would be...... kg-m. 1 (a) 100 (b) 160 (c) 50 (d) 40 B, 1993)

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