52 . There are ways of distributing the cards to the four players. Call these four players A, 13, 13, 13, 13 B, C, and D. There is only one way of distributing the cards so that player A receives all red cards, player B receives all yellow cards, player C receives all blue cards, and player D receives all green cards. However, there are 4! ways of assigning the four colors to the four players and therefore there are 4! ways of distributing the cards so that each player receives 13 cards of the same color. So, the probability we need is
52 . There are ways of distributing the cards to the four players. Call these four players A, 13, 13, 13, 13 B, C, and D. There is only one way of distributing the cards so that player A receives all red cards, player B receives all yellow cards, player C receives all blue cards, and player D receives all green cards. However, there are 4! ways of assigning the four colors to the four players and therefore there are 4! ways of distributing the cards so that each player receives 13 cards of the same color. So, the probability we need is
Chapter9: Sequences, Probability And Counting Theory
Section9.5: Counting Principles
Problem 40SE: A family consisting of 2 parents and 3 children is to pose for a picture with 2 family members in...
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Transcribed Image Text:52
1. There are
ways of distributing the cards to the four players. Call these four players A,
13, 13, 13, 13
B, C, and D. There is only one way of distributing the cards so that player A receives all red cards,
player B receives all yellow cards, player C receives all blue cards, and player D receives all green cards.
However, there are 4! ways of assigning the four colors to the four players and therefore there are 4!
ways of distributing the cards so that each player receives 13 cards of the same color. So, the probability
we need is
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