50 m/s 40 m/s 30 m/s 45° ER=91.8 m- R=163 m- R=255 m (a) Vo = 50 m/s 75 45 R= 128 m- R=255 m (b) actories of proiectiles on level ground. (a) The greater the initial sneed Vo. the greater the range for a given initial

In measuring values of distance and height, we can assume that measurements can be made with a measurement error of 0.05 m. Assume a projectile is launched horizontally with a height of 3 m, with a resulting range of 21.1 m. Using Min/Max and the equations of motion for a projectile, determine the time of flight of the projectile with most probable error.

In What If? section of Example 4.5(phys.png), it was claimed that the maximum range of a ski jumper occurs for a launch angle θtheta given by where ϕ is the angle the hill makes with the horizontal in Figure 4.14. Prove this claim by deriving the equation above(it an image eq.png).

A ground-to-ground projectile is shot with an initial velocity of 18 m/sat angle 54 degrees, measured from the horizontal. Neglecting air-resistance, what is the range of the projectile (the maximum horizontal distance in meter)?

A river of width' a' with straight parallel banks flows due north with speed u. The points O and A are on opposite banks and A is due east of O. Coordinate axes Ox and Oy are taken in the east and north directions respectively. A boat, whose speed is v relative to water, starts from O and crosses the river. If the boat is steered due east and u varies with x as: u = x(a – x). Find: equation of trajectory of the boat

suppose that you are Napoleon at the Battle of Waterloo. Your cannons have just arrived. the British are 1400 m to 1550 m away. the cannons you are using have muzzle velocities of 118 m/s and 200 m/s. Which cannons will you use and at what angle will you set them. there are two angles that will give the same distance for each cannon. one is greater than 45 degrees and one is less than 45 degrees. See if you can find both angles to use for each cannon, simply by trial ans error. then you have twice the firepower.

Given the acceleration as a function of the angle theta, a =6.5sinθ + 2.3cosθ. Find the optimal angle, so the acceleration is maximum Find the value of the maximum acceleration I have found the derivative of the function but am confusing myself on the next steps.

For the following exercises, use this scenario: A dart is thrown upward with an initial velocity of 65 mm per second at an angle of elevation of 52°. Consider the horizontal and vertical positions of the dart at any time t. Neglect air resistance. Discuss why this situation can be modeled using parametric equations. Discuss how you determined all possible values for t that represent the situation. What do maximum and minimum values of the parametric equations represent in this context?

I need some help with finding the velocity in section 1.1, and also solving 1.2. I believe the projection angle is 45 degrees. Thanks!

SOLVE STEP BY STEP IN DIGITAL FORMAT In the following problem, break down the procedure by placing: Data, Formula / Clearances, Operations and Result If Captain Marvel throws Spiderman against Thanos to remove his gauntlet, with a throw of 800 meters, with what speed should the tour start? Consider that the Captain uses a 50º angle, measured with her digital protractor. What was her flight time and what maximum height did she reach in her trajectory?