5. Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of heat? a. 50.0 g Al, CAI = 0.903 J/g °C b. 50.0 g Cu, Ccu = 0.385 J/g°C c. 25.0 g granite, Cgranite = 0.79 J/gᵒC d. 25.0 g Au, CAu = 0.128 J/g °C e. 25.0 g Ag, CAg = 0.235 J/g°C

What is the amount of heat (value of q) when 22.8 g of aluminum is heated from 20.0°C to 425°C? The specific heat capacity of aluminum is Cs AL = 0.900 J/g°C. Select one: a. –1.19 x 10^3 J b. 52.2 J c. none of these d. -52.2 J e. 405 J f. 1.19 x 10^3 J g. 2.94 J h. -405 J i. 8.31 x 10^3 J j. -8.31 x 10^3 J

How many joules of heat are needed to raise the temperature of a 1.55-kg block of metal from 23.0°C to 77.5°C? The specific heat capacity of the metal block is 0.385 J/g.K. O 19.4 J O 2.66 × 104 J 26.6 J 3.255 × 104 J 5.58 x 10-6 J

What is the amount of heat (value of q) when 22.8 g of gold is heated from 20.0℃ to 425℃? The specific heat capacity of gold is Cs,Au = 0.129 J/g℃. Select one: a. 2.94 J b. 405 J c. none of these d. –405 J e. –1.19 x 10^3 J f. –1.07 x 10^3 J g. 1.07 x 10^3 J h. 52.2 J i. 1.19 x 10^3 J j. –52.2 J

If a 50.0g sample of Al at 20.0 oC absorbs 650.0J or heat, what will it’s final temperature be? c=o.897 J/g oC

Find the final temperature Suppose we mix 90.0 grams of hot water (90.0°C) with 10.0 grams of cold water (10.0°C). Let x = the final temperature. C=4.184 J/g.°C a. Set up an expression for the energy released (q) by the hot water (Aqhot motCAThot) b. Set up an expression for the energy absorbed (q) by the cold water (Aqcold=mcold CATcold) c. Calculate Tf

35 g of water at 40 C and 95 g of water at 60 C are mixed. What is the temperature of this mixture ? Specific heat capacity of water = 4.184 J/g.C. 58 C 48 C 55 C 45 C

Which material will show the smallest temperature change upon absorbing the same amount of heat (SH specifi c heat)? Assume the same mass and initial temperature for all materials. O SH Au - 0.128 J/g°C O SH ethanol = 2.42 J/g°C O SH Fe = 0.449 J/g°C O SH H 20 = 4.18 J/g°C

A sample of 175°C copper is placed into a beaker with 100 grams of 25°C water. Which sample of copper will heat the water to the lowest final temperature? The specific heat of copper is 0.385 J-g-1.°C-1. The specific heat of water is 4.184 J·g-1.°C-1. A. 5.0 g Cu B. 2.0 g Cu C. 0.5 g Cu D. 1.0 g Cu

Do not give handwriting solution.