please show all work and detailed explanation of what do results mean 5. To examine the effects of pets and friends in stressful situations, researchersrecruited 40 people to participate in an experiment. Subjects were randomlyassigned to one of three groups to perform a stressful task alone (control group),with a good friend present, or with their dog present. Each subjects mean heart rateduring the task was recorded. Higher heart rates mean more stress. Use an alpha of.05.Controln₁ = 12M₁ = 85.7$1 = 3.4SS 127.16SSBetween 263.01Petsn2 = 14M₂ = 83.2S2 = 2.5SS=81.25a) What are the hypotheses for this test?b) What is the critical value?Friendsn3 = 14M3 89.3S3 = 3.5SS= 159.25c) Complete the necessary calculations (include post hocs if necessary).d) Report your results in APA stylee) Interpret the results and include a source table.6 A relationshin vrart want to know if people with higher levels of emotional

Since you have posted a question with multiple subparts, we will solve first three subparts for you. To get remaining subparts solved, please repost the question and mention the subparts to be solved. Anova is the measure of parametric test. It is the extension model of two sample independent t test. It compares three or more groups mean. It provide the variation exist between and within the groups of observations. It use F test to explain the variation. a) Given : Effects of pets and friends in the stressful situations is studied. Claim : Mean stress level is different for three groups Let the null and alternate hypothesis be : Null hypothesis : There is no significance mean difference of stress level among three groups i.e. H0 : μ1=μ2=μ3 Alternate hypothesis : There is significance mean difference of stress level among three groups i.e. Ha : μ1≠μ2≠μ3b) Given : Number of treatment is 3 Degree of freedom for between treatment : dfbetween=k-1=3-1=2 Total number of observations is three groups is 40 i.e. 12+14+14 Degree of within treatment : dfwithin=n-k=40-3=37 Two tail is used. Level of significance is 0.05 The F critical value at 0.05 level of significance for (2,37) degree of freedom is 3.252 Excel code for critical value is F.INV.RT(0.05,2,37)c) Given : From the information given : Between sum of square is 263.01 Within sum of square : SSW=∑SSi=127.16+81.25+159.25=367.66 Total sum of square : SST=SSB+SSW=263.01+367.66=630.67 Anova table will be : Source DF SS MSS F F critical Decision Between 2 263.01 263.012=131.505 131.5059.937=13.234 3.252 F>F critical Null hypothesis is rejected Within 37 367.66 367.6637=9.937 Total n-1=40-1=39 630.67 Thus, the null hypothesis is rejected and there exist significance difference between each groups. The t critical value for 37 degree of freedom at 0.05 level of significance is 2.03 Excel code for critical value is T.INV.2T(0.05,37) Comparison Mean difference CD Conclusion Significance or not Control vs Pets 85.7-83.2=2.5 t0.05,37×MSW×1nC+1nP=2.03×9.937×112+114=2.52 MD<CD It shows significant difference Control vs Friends 85.7-89.3=3.6 t0.05,37×MSW×1nC+1nP=2.03×9.937×112+114=2.52 MD>CD It does not shows significant difference Pets vs Friends 83.2-89.3=6.1 t0.05,37×MSW×1nC+1nP=2.03×9.937×114+114=2.42 MD>CD It does not shows significant difference

Answered: 5. To examine the effects of pets and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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please show all work and detailed explanation of what do results mean

5. To examine the effects of pets and friends in stressful situations, researchers
recruited 40 people to participate in an experiment. Subjects were randomly
assigned to one of three groups to perform a stressful task alone (control group),
with a good friend present, or with their dog present. Each subjects mean heart rate
during the task was recorded. Higher heart rates mean more stress. Use an alpha of
.05.
Control
n₁ = 12
M₁ = 85.7
$1 = 3.4
SS 127.16
SSBetween 263.01
Pets
n2 = 14
M₂ = 83.2
S2 = 2.5
SS=81.25
a) What are the hypotheses for this test?
b) What is the critical value?
Friends
n3 = 14
M3 89.3
S3 = 3.5
SS= 159.25
c) Complete the necessary calculations (include post hocs if necessary).
d) Report your results in APA style
e) Interpret the results and include a source table.
6 A relationshin vrart want to know if people with higher levels of emotional

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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