Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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i have this problem and its solution can someone explain the solution to me step by step im confused please thank you!!
![• Use cibi + c₂b₂ + c3b3= F(t), solve for C₁, C₂, and cz
b₁ : 1+ t² = 1 + ot + 1 t ² = (1,0,1))
b₂i2t-t² = 0 + Zt-1t ²₂ (0, 2, -1)
53:1=t+t² = 1−1+ +1 +² ₂ (1₁-1, 1)
=
→
Plt) = 6+4t+3+² (6₁4,3)
=
6
4
→ Resulting System
Z
-1 |
R₁-R32 R370
Бий
ZR3-R2>R3;
3
3
6
5. The set B = {1+ t², 2t - t²,1 −ť + ²) is a basis for P₂. Find
the Coordinate vector of p(t) = 6 + 4t + 3t² relative to "B".
<2
<₁ + <3 = 6 → ²₁+2=6 C₁=4
кг
2c₂-c²3= 4 ⇒ 202-2=4><₂ = 3
C3 = 2 (C3=2
Put into columin
vectors to form
the matrix
Thus, the coording te vector
"B" is
relative
to
of
[P]B = [²] - [
C3
p(t).
41 02 03
7
NW F
242
6
나](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4686411-1175-4406-9c2d-bb6b8b762804%2F273ca36f-ba10-4dbb-8e6f-3f0aaa1f8135%2F4ejkamk_processed.png&w=3840&q=75)
Transcribed Image Text:• Use cibi + c₂b₂ + c3b3= F(t), solve for C₁, C₂, and cz
b₁ : 1+ t² = 1 + ot + 1 t ² = (1,0,1))
b₂i2t-t² = 0 + Zt-1t ²₂ (0, 2, -1)
53:1=t+t² = 1−1+ +1 +² ₂ (1₁-1, 1)
=
→
Plt) = 6+4t+3+² (6₁4,3)
=
6
4
→ Resulting System
Z
-1 |
R₁-R32 R370
Бий
ZR3-R2>R3;
3
3
6
5. The set B = {1+ t², 2t - t²,1 −ť + ²) is a basis for P₂. Find
the Coordinate vector of p(t) = 6 + 4t + 3t² relative to "B".
<2
<₁ + <3 = 6 → ²₁+2=6 C₁=4
кг
2c₂-c²3= 4 ⇒ 202-2=4><₂ = 3
C3 = 2 (C3=2
Put into columin
vectors to form
the matrix
Thus, the coording te vector
"B" is
relative
to
of
[P]B = [²] - [
C3
p(t).
41 02 03
7
NW F
242
6
나
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