Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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The Mitchell family took a road trip from Detroit to Toronto. Their route was 750 kilometers long and required 54
liters of gas. 

(a) What was the fuel efficiency in miles per gallon? Round to the nearest tenth.

(b) Suppose the Mitchells plan to drive to Washington, D.C. on their next road trip. Assuming they get the same
mileage as you calculated in part a, calculate the cost of their 1060-mile route if gasoline costs $2.35 per
gallon. 

### Road Trip Fuel Efficiency Calculation and Cost Analysis

The Mitchell family took a road trip from Detroit to Toronto. Their route was 750 kilometers long and required 54 liters of gas.

#### (a) Fuel Efficiency Calculation (in miles per gallon)

To find the fuel efficiency in miles per gallon, follow these steps:

1. Convert kilometers to miles:
   - 1 kilometer = 0.621371 miles
   - 750 kilometers * 0.621371 miles/kilometer ≈ 466.03 miles

2. Convert liters to gallons:
   - 1 liter = 0.264172 gallons
   - 54 liters * 0.264172 gallons/liter ≈ 14.27 gallons

3. Calculate miles per gallon (MPG):
   - MPG = miles / gallons
   - MPG ≈ 466.03 miles / 14.27 gallons ≈ 32.7 MPG

Thus, the fuel efficiency is approximately **32.7 miles per gallon**, rounded to the nearest tenth.

#### (b) Cost Calculation for a Trip to Washington, D.C.

Suppose the Mitchells plan to drive to Washington, D.C. on their next road trip, covering a distance of 1060 miles. Assuming they get the same mileage as calculated in part (a), let's calculate the cost of their trip if gasoline costs $2.35 per gallon.

1. Determine the number of gallons needed:
   - Gallons needed ≈ Miles driven / MPG
   - Gallons needed ≈ 1060 miles / 32.7 MPG ≈ 32.4 gallons

2. Calculate the total cost:
   - Total cost ≈ Gallons needed * Cost per gallon
   - Total cost ≈ 32.4 gallons * $2.35/gallon ≈ $76.14

Thus, the cost of the 1060-mile trip to Washington, D.C. would be approximately **$76.14**.

This breakdown of calculations ensures students understand the conversion between units and how to apply ratios for real-world problems.
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Transcribed Image Text:### Road Trip Fuel Efficiency Calculation and Cost Analysis The Mitchell family took a road trip from Detroit to Toronto. Their route was 750 kilometers long and required 54 liters of gas. #### (a) Fuel Efficiency Calculation (in miles per gallon) To find the fuel efficiency in miles per gallon, follow these steps: 1. Convert kilometers to miles: - 1 kilometer = 0.621371 miles - 750 kilometers * 0.621371 miles/kilometer ≈ 466.03 miles 2. Convert liters to gallons: - 1 liter = 0.264172 gallons - 54 liters * 0.264172 gallons/liter ≈ 14.27 gallons 3. Calculate miles per gallon (MPG): - MPG = miles / gallons - MPG ≈ 466.03 miles / 14.27 gallons ≈ 32.7 MPG Thus, the fuel efficiency is approximately **32.7 miles per gallon**, rounded to the nearest tenth. #### (b) Cost Calculation for a Trip to Washington, D.C. Suppose the Mitchells plan to drive to Washington, D.C. on their next road trip, covering a distance of 1060 miles. Assuming they get the same mileage as calculated in part (a), let's calculate the cost of their trip if gasoline costs $2.35 per gallon. 1. Determine the number of gallons needed: - Gallons needed ≈ Miles driven / MPG - Gallons needed ≈ 1060 miles / 32.7 MPG ≈ 32.4 gallons 2. Calculate the total cost: - Total cost ≈ Gallons needed * Cost per gallon - Total cost ≈ 32.4 gallons * $2.35/gallon ≈ $76.14 Thus, the cost of the 1060-mile trip to Washington, D.C. would be approximately **$76.14**. This breakdown of calculations ensures students understand the conversion between units and how to apply ratios for real-world problems.
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