5. Suppose X is the number of successes in a random sample of size n from a large population with aproportion of success p. What are the mean and the standard deviation of the sampling distribution of Xin terms of n and p?The mean is p(l-pland the standard deviation is p(1-p)b. The mean is npand the standard deviation is ap(1-p).The mean is p(1-pland the standard deviation is pp.C.d.The mcan is 7pand the standard deviation is rp.

Answered: Image /qna-images/answer/e6ccce19-bdec-4954-9fea-a8dbe96e468f.jpg

Answered: 5. Suppose X is the number of successes…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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20. Sampling distribution. From 1975 through 2016, the mean gain of the Down jones industrial average was 470. A random sample of 32 years is selected from population. What is the probability that the mean gain for the sample was between 200 and 500. The standard deviation of population is 1215
The mean weekly earnings of all female workers in a state is $710 and the mean weekly earnings of all male workers in the same state is $760. The standard deviations of the weekly earnings are $86 for the females and $106 for the males. Suppose we take one sample of 316 female workers and another sample of 329 male workers from this state. 1.1. By hand, what is the mean of the sampling distribution of the difference between the mean weekly earnings for females and males? 1.2. By hand, what is the standard deviation of the sampling distribution of the difference between the mean weekly earnings for females and males, rounded to two decimal places?
This is for statistics and probability
4. The time required for all cross-country skiers to complete a race has a normal distribution with a mean of 46 minutes and a standard deviation of 6 minutes. You choose a random sample of six skiers, and the mean of the sample is denoted i. What are the mean and standard deviation of ?
Recent studies have shown that about 16% of American adults fit the medical definition of being obese. A large medical clinic would like to estimate what percentage of their patients are obese, so they take a random sample of 400 patients and find that 52 are obese. Suppose that in truth, the same percentage holds for the patients of the medical clinic as for the general population, 16%. Find the mean of the sampling distribution of p̂.
A population of values has a normal distribution with mean= 155.4 and standard deviation= 21.8. do you intend to draw a random sample of size n= 244. A. Find P81, which is the value(X) separating the bottom 81% values from the top 19% values. B. Find P81, which is the sample mean separating the bottom 81% sample needs from the top 19% sample means.
Suppose X, Y and Z are 3 random variables. The mean of X is 2. The mean of Y is 3. The mean of Z is 4. The standard deviations are 1, 2, and 3 (in the same order). The correlation between any two is -1/4. Find the mean and variance of T = X +Y+ 2Z.
Suppose a professor uses a normal distribution to assign grades in her math class. • She assigns an A to students scoring more than 1.9 standard deviations above the mean. • She assigns an F to students scoring more than 2.2 standard deviations below the mean. She assigns a B to students who Score between 1 and 1.9 standard deviations above the mean. • She assigns a D to students who Score between 1.2 and 2.2 standard deviations below the mean. • All other students get a C. Use the Cumulative Z-Score Table to answer the following questions. The Z-Score Table can be found below by selecting "Read". Write your answer as a percent using 2 decimal places. What percent of the class receives each grade assuming the scores are normally distributed? Hint % will recieve an A % will recieve a B % will recieve a C % will recieve a D % will recieve an F
24. How does the t distribution differ from the Z distribution? a. It has a smaller standard deviation and hence thinner tails than the Z distribution. b. It has a larger standard deviation and hence thicker tails than the Z distribution. c. The t and Z distributions are no different.
In a poll conducted by the General Social Survey, 81% of respondents said that their jobs were sometimes or always stressful. Suppose a sample of 500 adults is takes and the proportion that say their jobs were sometimes or always stressful is recorded. Assuming np(1-p) > 10, what is the standard deviation of the sampling distribution of the sample proportion for this problem?
Suppose Jack and Diane are each attempting to use a simulation to describe the sampling distribution from a population that is skewed right with mean 60 and standard deviation 5. Jack obtains 1000 random samples of size n=5 from the population, finds the mean of the means, and determines the standard deviation of the means. Diane does the same simulation, but obtains 1000 random samples of size n=30 from the population What do you expect the mean of Jack's distribution to be? What do you expect the mean of Diane's distribution to be?
3. Let X be the mean of a random sample of n = 25 from the distribution with a mean of 30 and a variance of 9. Find an approximated probability that the sample mean is between 29.8 and 30.6.

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