5. Suppose that Joe is a grocery store clerk. The time \( X \) (in minutes) that Joe spends checking out a randomly selected customer has a probability density function (pdf)\[f(x) = \frac{5x^4}{243} \cdot e^{-\left(\frac{x}{3}\right)^5} = \frac{5x^4}{243} \cdot \exp \left( -\left( \frac{x}{3} \right)^5 \right), \quad 0 < x < \infty.\]What is the probability that Joe will spend at least 4 minutes checking out his next customer?

# X be the time spend by Joe's with given pdf :f(x)=5*x^4/243 *e^-x/3)^5 ;x>0 then to find…

Answered: 5. Suppose that Joe is a grocery store…

A First Course in Probability (10th Edition)

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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5. Suppose that Joe is a grocery store clerk. The time X (in minutes) that Joe spends checking out a randomly selected customer has probability density function (pdf) 5x4 ·e-(x/3)5 243 5x1 f (x) 0