5. Planck's equation relates the energy of a photon of light to its frequency. E= hv Where Planck's constant h =6.64 x 10-34 J-s And frequency (v) is measured in 1/seconds or hertz (Hz) If the frequency of a red spectral line is 1.60 x 1014 Hz, how much energy does one photon of this light have? a. b. If the frequency of a violet spectra line is at 2.50 x 1014 Hz, how much energy does one photon of this light have?

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5. Planck's equation relates the energy of a photon of light to its frequency.
E= hv
Where Planck's constant h =6.64 x 10-34 J.s
And frequency (v) is measured in 1/seconds or hertz (Hz)
If the frequency of a red spectral line is 1.60 x 1014 Hz, how much energy does one
photon of this light have?
a.
b. If the frequency of a violet spectra line is at 2.50 x 1014 Hz, how much energy does one
photon of this light have?
6. The visible light spectrum represents only a small portion of the electromagnetic spectrum.
Infrared and ultraviolet radiations lie directly outside the visible
range.
* UV radiation is dangerous and is located just past the violet region on the spectrum.
*IR radiation is harmless and is located just before the red region on the spectrum.
Based on your calculations in question 5 above, explain why you think UV is more dangerous
than IR.
Transcribed Image Text:5. Planck's equation relates the energy of a photon of light to its frequency. E= hv Where Planck's constant h =6.64 x 10-34 J.s And frequency (v) is measured in 1/seconds or hertz (Hz) If the frequency of a red spectral line is 1.60 x 1014 Hz, how much energy does one photon of this light have? a. b. If the frequency of a violet spectra line is at 2.50 x 1014 Hz, how much energy does one photon of this light have? 6. The visible light spectrum represents only a small portion of the electromagnetic spectrum. Infrared and ultraviolet radiations lie directly outside the visible range. * UV radiation is dangerous and is located just past the violet region on the spectrum. *IR radiation is harmless and is located just before the red region on the spectrum. Based on your calculations in question 5 above, explain why you think UV is more dangerous than IR.
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