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5. Hence show that: OU (hvexp(-ßhv)) hv exp(-2ẞhv) =-3Nhv + οβ (1-exp(-ẞhv)) (1-exp(-Bhv)) Hint 1: you will need to use the quotient rule: f'(x) yf'(x) xf'(y) f'(y) (f'(y))² (f'(y))²

5. Hence show that: OU (hvexp(-ßhv)) hv exp(-2ẞhv) =-3Nhv + οβ (1-exp(-ẞhv)) (1-exp(-Bhv)) Hint 1: you will need to use the quotient rule: f'(x) yf'(x) xf'(y) f'(y) (f'(y))² (f'(y))²

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5. Hence show that: OU (hv exp(-Bhv)) hv exp(-2ẞhv) =-3Nhv + οβ (1-exp(-ẞhv)) (1-exp(-ßhv))² Hint 1: you will need to use the quotient rule: yf'(x) xf'(y) f'(x) f'(y) (f'(y))² (f'(y))² Hint 2: the following identity will avoid you having to use the chain rule: d (1-e√(x)) = -f'(x)e√(x) dx
Transcribed Image Text:5. Hence show that: OU (hv exp(-Bhv)) hv exp(-2ẞhv) =-3Nhv + οβ (1-exp(-ẞhv)) (1-exp(-ßhv))² Hint 1: you will need to use the quotient rule: yf'(x) xf'(y) f'(x) f'(y) (f'(y))² (f'(y))² Hint 2: the following identity will avoid you having to use the chain rule: d (1-e√(x)) = -f'(x)e√(x) dx
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