5. Consider the following equilibrium in a closed vessel:  H 2 (g) + I 2 (g)------- >2 HI (g) H = +53 kJ/mol a) If more I 2 (g) is added to the vessel, the forward reaction rate will ___________________ while the reverse reaction rate ___________________. b) If HI (g) is removed from the vessel, the forward reaction rate will ___________________ while the reverse reaction rate ___________________. c) If a catalyst is added to the vessel, the forward rate will ___________________ while the reverse rate ___________________. The catalyst lowers the ___________________ for both the forward and reverse reactions and speeds them up ___________________.

5. Consider the following equilibrium in a closed vessel: 
H 2 (g) + I 2 (g)------- >2 HI (g) H = +53 kJ/mol
a) If more I 2 (g) is added to the vessel, the forward reaction rate will
___________________ while the reverse reaction rate ___________________.
b) If HI (g) is removed from the vessel, the forward reaction rate will
___________________ while the reverse reaction rate ___________________.
c) If a catalyst is added to the vessel, the forward rate will ___________________
while the reverse rate ___________________. The catalyst lowers the
___________________ for both the forward and reverse reactions and speeds them
up ___________________.
d) Increasing the temperature for an endothermic reaction causes Kc to
________________. So now Q is ____________ than Kc and the reaction will shift
________________.

6. Consider the following equilibrium in a closed flask at some temperature. 


2 H 2 (g) + CO (g)------------ CH 3 OH (g) H = -90.2 kJ/mol
a. Write the expression for the reaction quotient, Q.
b. Will the reaction quotient increase, decrease or be unaffected if …
a) H 2 is added to the flask ___________________
b) CH 3 OH is added to the flask ___________________
c) CO is removed from the flask ___________________

d) A catalyst is added to the mixture ___________________
e) If the volume of the flask were doubled, what would be the effect on Q? Bequantitative.