MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- In the General Social Survey, respondents were asked "If your party nominated a woman for President, would you vote for her if she were qualified for the job?" A two-way table summarizing the results for 953 respondents, by gender, is shown below: Gender Female Male Total Vote for female candidate? Yes No 488 66 335 64 823 130 The chi-square test statistic = 3.35. At a significance level of 0.05, what is your conclusion? O The null hypothesis is not rejected: there is no association between gender and support for a female president Total 554 399 953 O The null hypothesis is rejected: there is an association between gender and support for a female president. O The null hypothesis is not rejected: there is an association between gender and support for a female president. ty O The null hypothesis is rejected: there is no association between gender and support for a female president. Q Search or enter address +arrow_forwardWhat are the values for SS and variance for the following sample of n = 3 scores? Sample: 8, 5, 2arrow_forward2. Interpret this data.arrow_forward
- A physician who specialized in weight control has three different plans he recommends. TTISIT As an experiment, he randomly selected 12 patients and then assigned 4 to each diet. After three weeks, the following weight losses, in pounds, were noted. Plan A Plan B Plan C 15 15 19 16 17 19 Grand Mean=17 14 19 21 15 17 17 Mean 2=17 Mean 3=19 Mean1=15 Use 0.05 significance level, to test if the plans are different. Question: Calculate the following, only: The SStotal, the SSE, the SST, dfT, dfE, VarT, VarE, and the test statistic F. Note: Write the details of your calculations for the Sum of Squares, only, and the final Result for the others. Type your answers on the Response Template. (without the formulas).arrow_forwardConsider the data below. Three random samples in different cities were selected. Water use per household per day were measured. City 1 City 2 City 3 70 66 66 70 64 66 55 45 54 60 41 61 65 58 65 45 44 65 55 46 Test the claim that the samples come from populations with the same mean. Assume all requirements have been met. Use a 5% level of significance. Identify the tail of the test. [ Select ] Find the P-value. I [ Select ) Will the null hypothesis be rejected? Select] Do the populations appear to have the same mean? [Sclectarrow_forward44arrow_forward
- What is the standard error for the independent sample t statistic for the two samples? Sample 1 n = 6, SS = 56 Sample 2 n = 4, SS = 40 Select one: 2.24 9.6 12 5arrow_forwardSuppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x= 100.1, y = 98.3, r=0.961, P-value = 0.000, and y = - 18.02 + 1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 100? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)arrow_forwardSuppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 102.13, y = 101.35, r= 0.927, P-value = 0.000, and y = 2.05 + 0.97x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 103? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r The best predicted value of y is (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r a = 0.05 a = 0.01 NOTE: To test Ho: p=0 Jagainst H,: p#0, reject H, lif the absolute value of r is greater than the critical value in the table. 4. 0.950 0.990 0.878 0.959 6 0.811 0.917 0.754 0.875 8. 0.707 0.834 0.666 0.632 0.602 9 0.798 10 0.765 11 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 0.468 0.456 18 0.590 19 0.575…arrow_forward
- give an example of a study for which the independent sample t-test is appropiatearrow_forward. Test the claim that the mean age of the prison population in one city is less than 26 years. Sample data are summarized as n=25, x=24.4, s=9.2. Use a significance level of a=0.05 Null and alternative hypothesis (give both in symbolic form and sentence form): Test statistic and p-value (show the calculation or show what you entered into the calculator (screenshots are ok here)): Technical conclusion, circle one: reject the null hypothesis or fail to reject the null hypothesis Why did you choose to reject or fail to reject the null hypothesis? Nontechnical conclusion addressing the original claim:arrow_forward
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