5. As a fundraiser you decide to invent a carnival game!! For the game a person pays 85 and rolls a pair of dice, and adds them together to get the total. The table below shows the payout fo number rolled. (This does not include the $5 you need to pay to play.) 2 3 6 I Roll Payout Net Gain/Loss a) Make the probability distribution function for rolling a pair of dice and finding the sum of the d 5 10 20 8 6 7 8 9 40 20 10 4 5 10 8 11 6 9 10 11 12 Net Gain/Los P(1) b) Find the expected value of this game. Explain what the expected value means in terms of this g c) The way the game is designed, would this be a good fundraiser? Be sure to explain why.

Two dice are rolled at the same time. Find the probability of each event listed when the probability is given as P(die 1, die 2). For example, if you want to know the probability that you roll a 3 on the first die and and a 5 on the second die, it would be written as P(3, 5). Give your answer as a decimal rounded to the thousandth place (three numbers after the decimal). P(1, 1) = P(both odd) P(even, odd): P(2 anywhere) = P(sum of 8) = P(sum of 1) =

Answer #30 please. Show work.

Activity #4: PROBABILITY Read and analyze the problems, show your solution, and box the answer. 1. What would be the probability of a. picking a black card at random from a standard deck of 52 cards? b. picking a face card (i.e. a king, queen, or jack)? c. not picking a face card? 2. What is the probability of rolling, on a fair dice: a. a 3? b. an even number? c. zero? d. a number greater than 4? e. a number lying between 0 and 72 f. a multiple of 3 given that an even number was drawn? 3. A standard deck of playing cards is well shuffled and from it, you are given two cards. You can have 0, 1, or 2 aces: three possibilities altogether. So, the probability that you have two aces is equal to 1/3. What is flawed about this argument? 4. You shuffle a deck of playing card, and then start turning the cards one at a time. The first one is black. The second one is also a black card. So is the third, and this happens up to the 10th card. You start thinking, "the next one will likely be red!"…