MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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**Question 5:**

An experiment consists of four outcomes with \( P(E1) = 0.2 \), \( P(E2) = 0.3 \), and \( P(E3) = 0.4 \). The probability of outcome \( E4 \) is _____.

**Options:**

- \( \bigcirc \) 0.100
- \( \bigcirc \) 0.500
- \( \bigcirc \) 0.900
- \( \bigcirc \) 0.024

**Explanation:**

According to the rules of probability, the sum of the probabilities for all possible outcomes of an experiment must equal 1. To find the probability of outcome \( E4 \), we calculate:

\[
P(E4) = 1 - P(E1) - P(E2) - P(E3) = 1 - 0.2 - 0.3 - 0.4 
\]

This gives us:

\[
P(E4) = 0.1
\]

Thus, the correct answer is 0.100.
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Transcribed Image Text:**Question 5:** An experiment consists of four outcomes with \( P(E1) = 0.2 \), \( P(E2) = 0.3 \), and \( P(E3) = 0.4 \). The probability of outcome \( E4 \) is _____. **Options:** - \( \bigcirc \) 0.100 - \( \bigcirc \) 0.500 - \( \bigcirc \) 0.900 - \( \bigcirc \) 0.024 **Explanation:** According to the rules of probability, the sum of the probabilities for all possible outcomes of an experiment must equal 1. To find the probability of outcome \( E4 \), we calculate: \[ P(E4) = 1 - P(E1) - P(E2) - P(E3) = 1 - 0.2 - 0.3 - 0.4 \] This gives us: \[ P(E4) = 0.1 \] Thus, the correct answer is 0.100.
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