College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C, at the end of 20 ns the electron's velocity will be approximately Group of answer choices 3.9 × 103 m/s. 4.4 × 106 m/s. 2.5 × 103 m/s. 3.0 × 108 m/s. 2.5 × 10–5 m/s.arrow_forwardAn electric field of 1 x 106 N/C acts on an electron, resulting in an acceleration of 1.3 x 1017 m/s2 for a short time. What is the magnitude of the radiative electric field observed at a location a distance of 3 cm away along a line perpendicular to the direction of the acceleration? i N/Carrow_forward3 sigarrow_forward
- Define the equation for the electron's velocity. Define the equation for the electron's position.arrow_forward1. A drop of oil (m = 8.000 × 10 7g) with excess negative charge is suspended between two horizontal charged plates by an electric field of magnitude 1.960 × 108 N/C. The plate spacing is 25.00 cm. (a) What is the direction of the electric force acting on the drop of oil? (Circle one.) Unable to be determined Up Down Left Right (b) What is the direction of the electric field acting on the drop of oil? (Circle one.) Left Right Unable to be determined Up Down (c) Choose the sign of the charge on each plate. (Circle one of each.) Upper plate: Positive Negative Unable to be determined Unable to be determined Lower plate: Positive Negative (d) Find the amount of charge on the drop of oil. (e) Determine the number of electrons stuck to the drop of oil. (f) Determine the voltage across the plates. Which plate is at a higher potential?arrow_forwardIn the configuration shown in the picture below, what is the total predicted angle for electric field at point a?arrow_forward
- 5. Two parallel, metal plates with separation distance d=2.00 cm carry charges of equal magnitude but opposite sign. Assume the electric field has a magnitude of 2,000 N/C. A charged particle with mass 2.00x10-16 kg and charge 1.00x106 C is projected from the center of the bottom negative plate with an initial speed of 1.00x105 m/s at an angle of 45 degrees above the horizontal. Assume the plates are square with side length 20.0 cm. a. Where does the particle strike? Answer: b. What is the minimum initial speed the particle must have in order to reach the positive plate. Answer:arrow_forward...arrow_forwardA point charge Q1 = -10.0 nC is at the origin, and a second point charge Q2 = +12.0 nC is on the x axis at x = 0.500 m. Consider the electric fields E, and E, at x = -1.00 m, generated by Q1 and Q2, respectively. Which of the following is true? A. E1 points to the right, E2 points to the left. В. Ei points to the left, E2 points to the right. С. E, points to the left, E, points to the left. D. E1 points to the right, E2 points to the right.arrow_forward
- A positive charge of magnitude Q1 = 0.45 nC is located at the origin. A negative charge Q2 = -6.5 nC is located on the positive x-axis at x = 17 cm from the origin. The point P is located y = 17 cm above charge Q2. a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. b) Calculate the y-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. c) Calculate the y-component of the electric field at point P due to the Charge Q2. Write your answer in units of N/C.arrow_forwardAn electron is projected into a uniform electric field that has a magnitude of 500 N/C. The direction of the electric field is vertically upward. The initial velocity of the electron has a magnitude of 6.00x10^6 m/s, and its direction is at an angle of 30°above the horizontal. Find:I. The maximum distance the electron rises vertically above its initial elevation.II. After what horizontal distance does the electron return to its original elevation.arrow_forward
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