5. An advertising company plans to market a product to low-income families. A study states that for a particular area, the average income per family is $24,596 and the standard deviation is $6256. If the company plans to target the bottom 18% of the families based on income, find the cutoff income.

Lunch break: In a recent survey of 655 working American ages 25-34, the average weekly amount spent on lunch was $44.60 with standard deviation $2.81. The weekly amounts are approximately bell-shaped. a. Estimate the percentage of amounts that are between $36.17 and $53.03. b. Estimate the percentage of amounts that are between $41.79 and $47.41. c. Between what two values will approximately 95% of the amounts be?

It is known that incomes from the USA follow a normal distribution with a mean of $55,000 and a standard deviation of $12,000.  A researcher took a sample of 100 people in the USA and obtained a sample mean of $67,000 with a standard deviation of $18,000.  What are the characteristics of the sampling distribution. A. Mean = $55,000 and Standard Deviation of the Mean = $1200 B. Mean = $55,000 and Standard Deviation of the Mean = $12000 C. Mean = $67,000 and Standard Deviation of the Mean = $569.21 D. Mean = $67,000 and Standard Deviation of the Mean = $1800

It has been reported that 84% of federal government employees use e- mail. If a sample of 235 federal government employees is selected, find the mean, variance, and standard deviation of the number who use e-mail. Round your answers to three decimal places. a. Find mean

The providence health maintenance organization wants to establish a criterion for recommending dietary changes if cholesterol levels are in the top 3%. What is the cutoff level for men aged 18 to 24 and the mean is 178.1 and the standard deviation is 40.7

Suppose there is a city where the mean cost per month of a one-bedroom apartment is $1,500, with a standard deviation of $250. Approximately what percentage of one-bedroom apartments in the city cost between $750 and $1,000?

Ef 610.

It is known that 41% of the population in the United States have brown eyes. Find the mean and standard deviation for the number of brown eyed people in a random group of 25 people in the United States. I cannot for the life of me figure this problem out.

On average, accountants earn approximately an average of $6500 per year in the United States. Assume that the distribution for electricians’ yearly earnings is normally distributed and that the standard deviation is $8680. Given a sample of 64 electricians, what is the standard deviation for the sampling distribution of the sample mean?   a. 1205 b. 8680 c. 6000 d. 1085

Consider the following data of 10 exams scores: 28, 57, 58, 64, 69, 74, 79, 80, 83, 85 1. The the mean, median, and mode       2. find the standard deviation without a graphing calculator. Show all your computations