Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- 9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.arrow_forwardWhat is the genotype of the parents of the corn dihybrid cross described above? What are the phenotypes of the parents of the corn dihybrid cross described above? What are the possible genotypes of the parent gametes of the corn dihybrid cross described above?arrow_forward9. A true-breeding blue-flower, wrinkled-seed, short-stem, yellow-leaf plant was crossed with a true-breeding red-flower, round- seed, long-stem, green-leaf plant and all of the progeny had the following phenotype: purple-flower, round seed, short-stem, approximately half of the leaves on the plants were yellow and the other half green. Assuming a single gene controls each trait, describe the inheritance pattern for each gene. Inheritance Pattern a. Gene Flower color Seed shape Stem length Leaf colorarrow_forward
- 3. Mendel crossed that was homozygous dominant for flower color and heterozygous for height with a plant that was heterozygous for flower color and homozygous recessive for height. Do a punnet square and calculate possible genotypes and phenotypes of this cross. Dominant for flower color = P (purple) Recessive for flower color = p (white) Dominant for height = T (tall) Recessive for height =t (short) %3D P1: PP X Tt Pp X tt PT Pt PT Pt Pt PPTT PPtt PPTT PPtt Pt PPTT PPtt PPTt PPtt pt PpTt Pptt PpTt Pptt pt PpIt Pptt PpTt Genotypes: Phenotypes: Genotypic Ratio: Phenotypic:arrow_forward5. If flower color shows codominance, and R = red and r = white, what will the %3D %3D offspring of a cross between RR x rr look like? * 100% red 75% red, 25% white 100% red and white 100% pink 25% red, 50% red and white, 25% whitearrow_forwardhomozygous recessive: 3) Round seeds are dominant over wrinkled seeds in pea plants. Fill in the Punnett square and determine the expected genotypes and phenotypes of the F₁ generation by crossing homozygous recessive and heterozygous parents. J Possible genotypes of offspring: Possible phenotypes of offspring: Percentage of offspring that are round: % of offspring that are homozygous dominant: heterozygous: J j J j J j j J j J j Fi generation If there were 3500 seeds collected, predict how many would be round? Predict how many seeds would be homozygous dominant? homozygous recessive: % wrinkled: % % homozygous recessive: wrinkled? heterozygous? % %arrow_forward
- 4). In papayas, sour fruit (S) is dominant over sweet fruit (s), and green skin (G) is dominant over yellow skin (g). The genes for these characteristics independently assort. A homozygous plant with sour fruit and green skin is crossed with a homozygous plant with sweet fruit and yellow skin. Two individuals from the F1 generation are then crossed to produce an F2 generation.arrow_forward. Set up the Punnett square for each of the following crosses. These crosses are all for the trait of round (dominant) vs. wrinkled (recessive) in sweet peas. 1. Rr x Rr What percentage off the offspring will be round? _____________________ 2. RR x Rr What percentage off the offspring will be round? _____________________ 3. Rr x rr What percentage off the offspring will be wrinkled? _____________________arrow_forwardR d 4. (3) D R and D are linked; the distance between R and D is 10 cM. G is unlinked. Now, you test cross this individual. a) (1) What % of the progeny of the test cross will be dominant for both R and D (ignore G)? b) Now, using all 3 genes, figure out the % of each gamete and they should all add up to 100%. I did one for you (see below). Make sure you know how to do a problem like this. These gametes are: RDG Rdg rDG RdG 22.5% rDg RDg rdGarrow_forward
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