5. A rectangular coil that has a length of 18.0 cm and a width of 6.5 cm containing 14 loops lies flat on your desk as shown on this page. A uniform magnetic field of magnitude 6.00 x 10-5 T points into this page. If a 6.00-A clockwise current flows through the coil, (a) determine the torque on the coil. N.m (b) which edge of the coil rises up? O O O O Top Bottom None of these Right

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**Problem 5: Electromagnetic Torque on a Rectangular Coil**

A rectangular coil has a length of 18.0 cm and a width of 6.5 cm, consisting of 14 loops, and lies flat on your desk as shown in the image. A uniform magnetic field of magnitude \(6.00 \times 10^{-5} \, \text{T}\) points into the page. If a 6.00 A clockwise current flows through the coil:

(a) **Determine the Torque on the Coil**
- The torque (\(\tau\)) on the coil is to be calculated. Use the formula:
  
  \[
  \tau = n \times I \times A \times B \times \sin(\theta)
  \]

  where:
  - \(n\) is the number of loops
  - \(I\) is the current in amperes
  - \(A\) is the area of the coil (\(A = \text{length} \times \text{width}\))
  - \(B\) is the magnetic field strength
  - \(\theta\) is the angle between the normal to the plane of the coil and magnetic field (assumed to be 90° if the field is perpendicular to the coil plane in the horizontal orientation)

(b) **Which Edge of the Coil Rises Up?**
- Multiple choice options:
  - Top
  - Bottom
  - None of these
  - Right
  - Left

**Visual Explanation:**
- The diagram shows a top view of a coil with several loops. The magnetic field is directed into the page, indicated by the uniform field lines. Depending on the resulting torque direction, one edge will rise based on Lenz’s law and the right-hand rule.
Transcribed Image Text:**Problem 5: Electromagnetic Torque on a Rectangular Coil** A rectangular coil has a length of 18.0 cm and a width of 6.5 cm, consisting of 14 loops, and lies flat on your desk as shown in the image. A uniform magnetic field of magnitude \(6.00 \times 10^{-5} \, \text{T}\) points into the page. If a 6.00 A clockwise current flows through the coil: (a) **Determine the Torque on the Coil** - The torque (\(\tau\)) on the coil is to be calculated. Use the formula: \[ \tau = n \times I \times A \times B \times \sin(\theta) \] where: - \(n\) is the number of loops - \(I\) is the current in amperes - \(A\) is the area of the coil (\(A = \text{length} \times \text{width}\)) - \(B\) is the magnetic field strength - \(\theta\) is the angle between the normal to the plane of the coil and magnetic field (assumed to be 90° if the field is perpendicular to the coil plane in the horizontal orientation) (b) **Which Edge of the Coil Rises Up?** - Multiple choice options: - Top - Bottom - None of these - Right - Left **Visual Explanation:** - The diagram shows a top view of a coil with several loops. The magnetic field is directed into the page, indicated by the uniform field lines. Depending on the resulting torque direction, one edge will rise based on Lenz’s law and the right-hand rule.
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